Parse error using &quot;.

Parse error using ".

pinehead18

here is what i have..

$output = "<option STYLE=background:blue ".if $dbselected == 'blue' { echo 'selected'; }.">blue";

It is giving me a prase error. If you could help at all i would appritiate it.

Thank you
- Anthony

stolzyboy

your if conditions need to be in ()

pinehead18

i just fixed that right before you posted...

and now it is

<option STYLE=background:blue ".if ($dbselected == 'blue') { echo 'selected'; }.">blue

and i'm still getting a parse error.

Any suggestions?

stolzyboy

<?
$dbselected = "blue";
//$dbselected = "green";
?>
<select>
<option>asdf</option>
<option>asdfddd</option>
<option>asdfsdfds</option>
<option STYLE="background:blue"<? if ($dbselected == "blue") echo " selected"; ?>>blue</option>
</select>

pinehead18

see the whole thing is it has to be inside $output = " " ;

is that even possible?

stolzyboy

any particular reason it has to be, you can't put if/else staments when you are assigning a variable = to something, you can do the check before hand, then put that variable into the $output

pinehead18

Yes.. I'm trying to make it check before hand.. Any suggestions on the best way to do that? So it checks before hand and keeps the right one selected?

stolzyboy

how are you getting your results, how many option boxes will there be

pinehead18

their are probably going to be about 20 option boxes

stolzyboy

are they displayed dynamically, or are they static in the code

pinehead18

static.. I jsut need it to have selected the one that is selected in the db.

Its all db powerd.. if option in db = blue i want the option blue to be selected.

stolzyboy

i am having i little bit of a hard time thinking of a decent way of doing it, it can be done, but it will be a kludge, you are making things hard on yourself, requiring everything to be in a variable like that but i will try and think of something

maybl8r03

Have you tried inline condition checks?


$arElements = array(
   "holloween"  =>   "Pumpkin",
   "christmas"   =>   "Egg Nog",
   "new year"   =>   "Champagne"
);

echo "<select name=\"variablename\">\n";
echo "<option value=\"\">...</option>\n";
reset($arElements);
while (list($strKey, $strValue) = each($arElements))
{
   echo "<option value=\"{$strKey}\"".
       ($strKey == @$_POST["variablename"] ?
            " selected=\"selected\""
       :
            ""
       ).
       ">{$strValue}</option>\n";
}
echo "</select>\n";

The advantage of

(conditioncheck? TRUE: FALSE)

is that it's perfect for simple logic and you can put them in between strings. It's a little harder to debug than the usual if..then..else statements but it's size is a big plus.

pinehead18

maybl8r03: That wont work will it cuase i am unable to then have $output = "<select boxes here>"; with the chceks inside their..

Will it?

maybl8r03

If you mean for this particular line in your original post:

$output = "<option STYLE=background:blue ".if $dbselected == 'blue' { echo 'selected'; }.">blue";

you'll just have to do:

$output = "<option style=\"background:blue\" ".($dbselected == "blue" ? "selected" : "") .">blue";

stolzyboy

btw, his solution, to help you to keep your sanity, is called a ternary operator, it is not widely used, but is a very good way of getting quick solutions like yours done, don't know why it didn't even cross my mind to do it that way, but it will work, sometimes that brain doesn't function when you tell it to, more info on the ternary can be found here

pinehead18

That works.. until i use several select options. Using the following code.. If i select blue it will select it next time i open the page. However, if i do the other ones with the other colors.. it wont select them.. Here is the code..

Any suggestions? Thank you
Anthony

<option STYLE=background:blue ".($dbselected == "blue" ? "selected" : "") .">blue
<option STYLE=background:royalblue ".($dbselected == "royalblue" ? "selected" :"") .">Royal Blue
<option STYLE=background:Cornflowerblue ".($dbselected == "cornflowerblue" ? "selected" : "") .">Cornflowerblue

maybl8r03

ahh...

I think you want to invoke a javascript call with the onchange trigger.

<html>
<body>
<form name="myform" action="?" method="GET">
<div id="mainbody" style="background:<?php echo @$_GET["color"]; ?>">
change background color:
<select name="color" onchange="document.all.mainbody.style.background=this.value;">
<?php
$allcolors = array(
   "blue"	=>	"Blue",
   "red"	=>	"Red",
   "green"	=>	"Green"
   );
while (list($syscolor, $showcolor) = each($allcolors))
{
	echo "<option value=\"{$syscolor}\" ".(@$_GET["color"]==$syscolor? " selected=\"selected\"":""). ">{$showcolor}</option>\n";
}
?>
</select>
<input type="button" name="anything" value="Refresh" onclick="submit();" />
</div>
</form>
</body>
</html>

If you refresh the screen it will remember but to make it remember per user or per session depends on the tools you will use to extend the memory (cookies or sessions).

stolzyboy

Originally posted by pinehead18
That works.. until i use several select options. Using the following code.. If i select blue it will select it next time i open the page. However, if i do the other ones with the other colors.. it wont select them..

not sure what you mean about when you select blue it selects it the next time, but with other colors it won't select them, are you trying to do multiple selects <select multiple> by any chance

pinehead18

No, like when i have those if statements just on blue.. it will work.. If blue is selected when i update the db then it will be selected when i go back to it late. However if the other colors are selected when i update the db the db will update however the color that is selected wont be updated.

Any ideas?
Thank you
Anthony