[Resolved] isint ??

[OhLordy]

How do you check if a number if an integer? Now, before everyone says is_int or is_integer that will return false for all info returned from forms. So use settype or (int) you say, well if it's a float or a double this will knock off the decimal place rather than return an error. So the only way I can think of is to $i%1==0. Is there another way?
Cheers
Rob

[rcmehta_14]

Yes, OhLordy there is a way for this.

As you mentioned is_int and is_integer doesn't work on form vars. But PHP has developed is_numeric function for this kind of variables.

if(!is_numeric($a)) $a = 0;

This way you can identify any integer or Float variable comes from a form.

Hope this works.

[OhLordy]

Thanks for the response rcmehta_14 but I am wanting to distinguish integers from floats. The reason for this is to display nicely readable ratios. I have now come up with this little function

<?
function get_divisor($x, $y)
{
  if($x%1!=0 || $y%1!=0)
    return false;
  for($i=0;$i<=($x>$y?$y:$x);$i++)
    $best=(($x%$i==0 && $y%$i==0)?$i:$best);
  return $best;
}
?>

Cheers
Rob

[Weedpacket]

Originally posted by OhLordy
Thanks for the response rcmehta_14 but I am wanting to distinguish integers from floats.

In that case, $num==intval($num) might do the job. Note though that it will pass "123.000" and -5 as integers.

That looks like a pretty nifty function, by the way; perhaps you could post it in the Echo Lounge Code Share thread?