Help with images showing with specific query

[VanPEP]

This is driving me crazy! How can I put an image on a page, then only have it show if a db query returns a specific value, but show nothing if the value dosent match? This is an example of what I was trying to do:

<?php if ($pdata = 'yes'?>
<img src="http://www.mypage.com/images/pic3.jpg width="64" height="64">
<?php } ?>

and it shows the pic alright if the $pdata = yes, but if it dosent = yes then it shows the broken image thing with the red x in it.

[barand]

<?php if ($pdata = 'yes'?>

should be

<?php if ($pdata = 'yes') { ?>

[VanPEP]

Sorry that was a typo in my post, the actual scripts is right, just dosent work correctly 😕

[barand]

Is missing quote after filname another typo?

Why not

<?php 
if ($pdata = 'yes') { 
echo "<img src=\"http://www.mypage.com/images/pic3.jpg\" width=\"64\" height=\"64\">"; 
} 
?> 

[VanPEP]

Now it just shows the picture - even if the db field is empty??

[barand]

Basic mistake - I missed it too

if ($pdata == 'yes') {

[VanPEP]

lol its always the simpliest mistakes that are hardest to spot

Thanks!