getting ip behind proxy

graziano

Hello

I am trying to use this script

http://www.cgsa.net/php/identifierShow.php

to know if the ip visitor is behind a proxy .

This script seems very good because it shows
$proxy : [1] if visitors is behind a proxy or $proxy : [] if
visitor is using a real ip .

The authour provided the functions , but now I am having problems to reproduce the outputs of the functions ....

Anyone can help me to reproduce the output of the functions on http://www.cgsa.net/php/identifierShow.php ?

Thank you very much

graziano

I tried

echo getVisitorIdentifier();
echo getSessionIdentifier();
echo getVisitParameters(1,10000) ;
echo initVisitPage(7500);
echo beginStandardForm($script,$method);

but only
getVisitorIdentifier();
and
getSessionIdentifier();
return a value ..

Other returning nothing or simply "array" .... 🙁

graziano

anyone can help please ?

Weedpacket

Have a look at the sample code being used in the demo (e.g., list())
Use print_r() to see what is in the arrays
Read through the code to see what the functions return and where their values come from
Note that the author is using register_globals instead of $_SERVER
Ask the author.

graziano

Originally posted by Weedpacket

Have a look at the sample code being used in the demo (e.g., list())
Use print_r() to see what is in the arrays
Read through the code to see what the functions return and where their values come from
Note that the author is using register_globals instead of $_SERVER
Ask the author.

[/B]

Thank you , I tried point 2 ,3 and 5 without success (point 1 and 4 are not clear to me 🙁 ) , please please anyone can help me to make work these functions ( I am going mad tried and retried) ?

graziano

bump

graziano

anyone please ?

johnassis

this code always works for me

if (getenv("HTTP_X_FORWARDED_FOR")) {
      $ip   = getenv("HTTP_X_FORWARDED_FOR");
    } else {
      $ip   = getenv("REMOTE_ADDR");
}
print"$ip";

graziano

still trying to return an output ... anyone please ?

johnassis

I don't really understand what you are after

still trying to return an output

Please be more specific on your description of what you want the script to do.

If you want to find out whether the visitor is using a proxy or not, which is the impression I got, you have to consider that some proxy softwares don't make it known.

I.E. getenv("HTTP_X_FORWARDED_FOR") will come out blank.

graziano

Thank you johnassis ..

I cannot understand how to give an output to this author
function

list($sid, $vid, $proxy, $string , $random) = getVisitParameters()

the result of the function should return something like this

$sid : [1063879990_26757]
$vid : [host41-40.pool212174.interbusiness.it]
$proxy : []
$string : [[212.171.44.44]]
$random : [2202]

Unluckly the author didn't place a php example to work with his functions (especially getVisitParameters) and my php knowledge level is not permitting me to solve this problem , I am going mad ...

Thank you