php onChange function Help

[The_broken]

Hi all...

I know nothing about java and very little about PHP coding.

I have an order/program form writen in php that needs to update when somebody selects from menu.

PHP:

<? show_hosting_menu($db->f("session_domain"),$i++,$db->f("session_id")); ?>

Is there a way to make this call an update tag.

<input type="hidden" name="action" value="update_domain">

the problem is that if nobody hits the update button befor checkout it never adds to basket.

Any help....

Thanks
The_broken

[majiclab]

Your post is not providing a whole lot of information for anyone to go off of. And your subject suggests you are trying to call PHP functions from JavaScript, which is impossible.

Try searching around for some articles that might touch on similar topics. It sounds like you are just starting out and maybe haven't looked out there too much.

There are some good articles on this site and many others, and if you are a teach-yourself kind of guy like I am, there's always the PHP reference on their site... 🙂

-Percy

[The_broken]

Hi majiclab...

No the problem I am having is that the php makes a drop down menu using database.

The call script is for drop down is.

<? show_hosting_menu($db->f("session_domain"),$i++,$db->f("session_id")); ?>

We need so when a customer selects anything from the above url to load another page. ( reload )

We where looking around this forum and see very little on this.

Thanks
The_broken

[majiclab]

In the generated HTML, add an onChange to the <SELECT>.

<SELECT onChange="location = '/path/to/new/url';">
...
</SELECT>

Hope that helps.

-Percy

[The_broken]

Hi majiclab..

I tried the above thing still no luck. Well I have enclosed the above dreamweaver txt file. Maybe this will help.

If you open you will see a hosting option php tag. Line 113.

Thanks

The_broken

😕

[majiclab]

Unfortunately without access to the show_hosting_menu() function, I can't determine what is wrong with the script...

-Percy

[The_broken]

// SHOW HOSTING OPTIONS & PRICES MENU
function show_hosting_menu($domain,$count,$id) {
$db = new ps_DB;
$q = "SELECT session_2 FROM sessions WHERE session_id = '$id'";
$db->query($q);
$db->next_record();
$default = $db->f("session_2");

$db = new ps_DB;
$q = "SELECT membership_setup,membership_name,membership_price,membership_id FROM membership WHERE membership_active='Y' ORDER BY 'membership_id'";
$db->query($q);

$style=  ' class="fields" ';

echo "<SELECT NAME=\"H[$count]\" class=\"fields\">";
while ($db->next_record()) {
	$dbn  = $db->f("membership_name");
	$dbp  = $db->f("membership_price");
	$dbi  = $db->f("membership_id");
	$dbs  = $db->f("membership_setup");
	$title = $dbn;
	$title.= " (";
	$title.= setup("currency");
	$title.= $dbp;
	$title.= ")";
	if ($dbs>0) {
		$title .= " + (" . setup("currency") . "" . $dbs . " setup)";
	}

	echo "<OPTION VALUE=\"$dbi\"";
	if ($default == $dbi) echo " selected";
	echo ">$title</OPTION>";
}

echo "</SELECT>";
return $ret;

}

This is the problem, script requires you to hit update before checkout.

Well some people don't hit update after they select package, is there an easy way to make onchange function.

I have enclosed the source that builds the menu.

Thanks
The_broken
😕

[majiclab]

Assuming your <FORM> tag is like this:

<FORM name="form_name">

Add this to the <SELECT> tag:

<SELECT onChange="document.forms['form_name'].submit();">

Depending on the name of the form, change the name the quotes above.

Hope that helps,

-Percy

[borntodie]

I'm still not exactly sure what you're trying to do but hopefully majiclab is on the right track.

The form doesn't appear to be named by looking at the text file.

 <form method="post" action="">

This needs to become:

 <form name="some_name" method="post" action="">

And then as majiclab said, in the show_hosting_menu() function code you need to change:

 echo "<SELECT NAME=\"H[$count]\" class=\"fields\">";

To:

 echo "<SELECT NAME=\"H[$count]\" class=\"fields\" onChange=\"document.forms['some_name'].submit();\">";

🙂

[The_broken]

<select NAME="H[0]" class="fields" onChange="document.forms['hosting_options02'].submit();"><option VALUE="5" selected>Dedicated Bronze #1 ($59.95)</option><option VALUE="6"> Dedicated Bronze #2 ($119.95) + ($99.95 setup)</option><option VALUE="7"> Dedicated Silver #1 ($149.95) + ($199.95 setup)</option><option VALUE="8"> Dedicated Silver #2 ($199.95) + ($299.95 setup)</option><option VALUE="9"> Dedicated Gold #1 ($99.95) + ($99.95 setup)</option><option VALUE="10"> Dedicated Gold #2 ($149.95) + ($199.95 setup)</option><option VALUE="11"> Dedicated Platinum #1 ($199.95) + ($299.95 setup)</option><option VALUE="12"> Dedicated Platinum #2 ($199.95) + ($299.95 setup)</option></select>

Still have small problem. I have included the html page that the script shows on the page.

The problem I am having is that the script makes the option list listed above and the onchange script does not send another option when selected.

As you can see I selected <option VALUE="5" selected>Dedicated Bronze #1 ($59.95)</option>

now if I select a diffrent one, it goes and reloads the page but it does not include the new option I selected.

These options are made by the database. is there a way for the onchange to input the option.

Am I missing something.

thanks
The_broken
😕