preg_replace

twopeak

Ok, I hate regular expressions, everytime I try, it fails...
could someone tell me why this doesn't work???

<?php
require 'functies.php';
$str = "this is a teststring (smile) blablabl :d) blablabla 🙂";

$q = mysql_query("SELECT * FROM smileys ORDER BY categorie");
while($l = mysql_fetch_object($q))
{
$bericht = preg_replace("/".preg_quote($l->code,"/")."/i","<img src='".$l->url."'>",$str);
}
echo "<br><br>",$bericht;

?>
it doesn't generate an error,it just doesn't replace my smileys (the 3 used exist)

paulnaj

Can you give a couple of literal examples of what $l->code look like.

twopeak

🙂
:d)
(smile)

(apple)
(ball)
😢
/)
:-\

all kinds of characters... that's why I used the preg_quote() function
Some of the codes have a space in front or behind, but not all of them...

paulnaj

Try this for the 1st arg to preg_replace() ...

"/".preg_quote(addslashes($l->code)),"/")."/i

... I think the problem is something to do with the fact that $l->code must be parsed into a string BEFORE being parsed into a regex.

Take the example smiley ...

:-\

... can't be put in double quotes to make a string ...

":-\"

... without adding the escape char ...

":-\"

This is before you consider using it as a regex, which would end up looking like ...

":-\\"

twopeak

YEAH
I found it!
there was 1 thing missing:

<?php
require 'functies.php';
$str = "Dit is een teststring (smile) met :d) smileys :)";
$bericht = $str;   //new
$q = mysql_query("SELECT * FROM smileys ORDER BY categorie");
while($l = mysql_fetch_object($q)) 
{
	$code = $l->code;
	$code =addslashes($code);
	$code = preg_quote($code, "/");
	$bericht = preg_replace("/".$code."/i","<img src='".$l->url."'>",$bericht);  //changed
}
echo "<br><br>",$bericht;

?>

Everytime there was a new smiley, it would search the original $str (without the img tags) for that smiley
so if I had tried with the last smiley, it would have worked for that last smiley, but not the others!!!

Thanks alot for the help!