Yet another question

[Paragon]

Im trying to not show a login box if the user is logged in.

if(isset($uid)) {
echo "Weclome $uid";
exit;
}

This doesnt work.

Any ideas how I could do this? I have all the connections and everything all in place.

[Skudd]

Where is $uid coming from? Is it a session variable?

[Paragon]

yes it is.

[Skudd]

Don't rely on globals like that. Use the superglobals.

For instance:

$_SESSION['uid']

Newer versions of PHP don't have support for globals by default. The above code is a more proper way of doing things.

[Paragon]

So this is a problem?

session_register("uid");

If I used it this way would I have to register it differnetly ?
Would I even use it like below ?

if(isset($_SESSION['uid'])) {
echo "Weclome $uid";
exit;
}

Thanks alot skudd

[Paragon]

<?
PLUGINTOP();
include("db.php");
if(!isset($uid)) {
include('config.php');
?>
<div class="border">
<div class="content">
Member Log In.<br /><br /> 
<form method="post" action="<?=$PHP_SELF?>">
<input type="text" name="uid" size="15"> Username<br /><br />
<input type="password" name="pwd" SIZE="15"> Password<br /><br />
<input type="submit" value="Log in">
</form>
</div>
</div>
 <? echo "logged in as $uid"; ?>
<?
exit;
}
session_register("uid");
session_register("pwd");
dbConnect("$db1");
$sql = "SELECT * FROM $userprefix WHERE userid = '$uid' AND password = '$pwd'";
$result = mysql_query($sql);
if (!$result) {
echo "error";
exit;
}
if (mysql_num_rows($result) == 0){
session_unregister("uid");
session_unregister("pwd"); 
include("config.php");
echo "Access Denied";  

exit; }
$fullnameprint = mysql_result($result,0,"fullname");
$emailaddressprint = mysql_result($result,0,"emailaddress");
$addpermission = mysql_result($result,0,"add2");
$editpermission = mysql_result($result,0,"edit2");
$deletepermission = mysql_result($result,0,"delete2");
$createpermission = mysql_result($result,0,"create2");
?>
<?
PLUGINBOTTOM();
?>

[okuto1973]

You have also to check if this variable is in session......i usually use this code:

if (session_is_registered(sess_variable)==true)
{
echo "Welcome $sess_variable";
}

Hope this help you!

[Paragon]

Thanks guys.

Do I have to pull it or somthing? I'm lost as to why its not working.

I have it set up pretty well. I had it setup for my admin area, but then I made sorta a portal page that displays the news. so I wanted to make a plugin or block that would have you login it works, but once im logged in it doesn't go away despite the great help you guys gave me.

<?
PLUGINTOP();
if (session_is_registered(uid)==true) 
{ 
echo "Welcome $uid";  

exit; 
} 
?>
<div class="border">
<div class="content">
Please Log In.<br /><br /> 
<form method="post" action="accesscontrol.php">
<input type="text" name="uid" size="15"> Username<br /><br />
<input type="password" name="pwd" SIZE="15"> Password<br /><br />
<input type="submit" value="Log in">
</form>
</div>
</div>
<?
PLUGINBOTTOM();
?>

That doesnt work. I must be doing somthing wrong if it works for you.

[Paragon]

HAHA does that mean no one knows? 😃

[laserlight]

I think you still should use the superglobal array.

[Paragon]

could you give me an example please.

[laserlight]

skudd has already given you an example.

[Paragon]

Ok well it doesnt work. Thats why I would like to see it used.

I use session_star() thinking thats the problem.

I get this.

Warning: session_start(): Cannot send session cache limiter - headers already sent (output started at /public_html/templates/template.txt:53) in /public_html/plugins/loginbox.php on line 3

[laserlight]

that means you used it after writing output.