Unix Timestamp Question

[rapmonkey]

Ok, say I have a number, such as "8752". How can I convert that to time? I want to know how many years, months, days, hours, minutes and seconds 8752 seconds is. How would I find this? Thanks! 😃

[barand]

$secs = 8752;

$mins = floor($secs/60);
$secs = $secs % 60;

$hrs = floor($mins/60);
$mins = $mins % 60;

$days = floor($hrs/24);
$hrs = $hrs % 24;

echo "$days days $hrs:$mins:$secs"

Beyond that months become a stumbling block. It depend on where you are in the year as they're different lengths

[cosminb]

if "8752" is a Unix timestamp() and you want find out what date it represesnts you could use date()
with the optional parameter.

Smth like this:
date('U', 8752)

[rapmonkey]

Originally posted by cosminb
if "8752" is a Unix timestamp() and you want find out what date it represesnts you could use date()
with the optional parameter.

Smth like this:
date('U', 8752)

8752 is a unix timestamp in the future minus the current unix timestamp. I want to find the months, days, etc. until that future unix timestamp.

[barand]

You could [man]getdate/man with both timestamps and subtract the respective array elements

[Weedpacket]

Originally posted by barand
You could [man]getdate/man with both timestamps and subtract the respective array elements

Remembering to carry when you get negative numbers for each element; an hour is sixty minutes, a minute is usually sixty seconds, and a day is usually twenty-four hours....