problem with the pic src

[aayatoos]

i want to display a picture in a table and the picture is stored in a folder named "files" and the picture name is stored in database in feild name "image_name"
so how can i write the src of the image
i tried the follow but it display an error

printf("<tr><td><font face='arial' size='6'><center><img src="files/%s" width = "120" height = "120"></center></font></td></tr>\n", $myrow["image_name"]);

can any body help me

[Weedpacket]

Looking at the colour-coding of your posted code, I can see that you've forgotten to escape your double quotes with \

[aayatoos]

it still does not work
i now tried this but the same error

printf("<tr><td><font face='arial' size='6'><center><img src="'files\'%s" width = "120" height = "120"></center></font></td></tr>\n", $myrow0["image_name"]);

[laserlight]

You're still missing 2 double quotes though.

You could use

printf("<tr><td><font face=\"arial\" size=\"6\"><center><img src=\"files%s\" width=\"120\" height=\"120\"></center></font></td></tr>\n", $myrow0["image_name"]);

or preferably (IMO)

echo '<tr><td><font face="arial" size="6"><center><img src="files' . $myrow0["image_name"] . '" width="120" height="120"></center></font></td></tr>' . "\n";

[aayatoos]

thank you laserlight
your code work
thaks again