[Resolved] Problem Uploading multiple images

[ihenman]

I have a form that takes in several images of homes to upload to the server, and store the path in my DB. The problem I'm having is if a file is not specified in the form (i.e. someone chooses not to upload a file for all possible entries) then my code stops at that particular selection.

heres a portion of the code so you can better understand what I mean.

//Copy main Pic
if($mainpic_name !="")
{
copy ("$mainpic", "./pictures/$mainpic_name")
or die("Main Picture: Could not copy file.");
echo "Main Picture: File $mainpic_name Uploaded Successfuly<br>";
}
else {die("No file specified.");}

//copy bedroom 1 pic
if($bdrm1_name !="")
{
copy ("$bdrm1", "./pictures/$bdrm1_name")
or die("Bedroom 1: Could not copy file.");
echo "Bedroom 1: File $bdrm1_name Uploaded Successfuly<br>";
}
else {die("Bedroom 1: No file specified for Bedroom 1 Picture.");}

//copy bedroom 2 pic
if($bdrm2_name !="")
{
copy ("$bdrm2", "./pictures/$bdrm2_name")
or die("Bedroom 2: Could not copy file.");
echo "Bedroom 2: File $bdrm2_name Uploaded Successfuly<br>";
}
else {die("Bedroom 2: No file specified Bedroom 2 Picture.");}

Example: If someone chooses not to upload a $mainpic for this house but they do uplaod pictures of the bedrooms, the Bedroom pictures never get copied to my picture directory. It more or less stops parsing the code right after the first variable that is empty. I know the code works if a user specifies files to upload for all possible variables.

Any one know what I need to add to make this work?

Thanks!

[okuto1973]

//Copy main Pic
if($mainpic_name !="")
{
copy ("$mainpic", "./pictures/$mainpic_name")
or die("Main Picture: Could not copy file.");
echo "Main Picture: File $mainpic_name Uploaded Successfuly<br>";
}

//copy bedroom 1 pic
if($bdrm1_name !="")
{
copy ("$bdrm1", "./pictures/$bdrm1_name")
or die("Bedroom 1: Could not copy file.");
echo "Bedroom 1: File $bdrm1_name Uploaded Successfuly<br>";
}

//copy bedroom 2 pic
if($bdrm2_name !="")
{
copy ("$bdrm2", "./pictures/$bdrm2_name")
or die("Bedroom 2: Could not copy file.");
echo "Bedroom 2: File $bdrm2_name Uploaded Successfuly<br>";
}

If you write a:
else {die("Bedroom 2: No file specified Bedroom 2 Picture.");}

sure the program stops if the image isn't loaded!

You could use a:

else {echo("Bedroom 2: No file specified Bedroom 2 Picture.");}

//Copy main Pic 
if($mainpic_name !="") 
{ 
copy ("$mainpic", "./pictures/$mainpic_name") 
or die("Main Picture: Could not copy file."); 
echo "Main Picture: File $mainpic_name Uploaded Successfuly<br>"; 
} 
else {echo("No file specified.");} 

//copy bedroom 1 pic 
if($bdrm1_name !="") 
{ 
copy ("$bdrm1", "./pictures/$bdrm1_name") 
or die("Bedroom 1: Could not copy file."); 
echo "Bedroom 1: File $bdrm1_name Uploaded Successfuly<br>"; 
} 
else {echo("Bedroom 1: No file specified for Bedroom 1 Picture.");} 

//copy bedroom 2 pic 
if($bdrm2_name !="") 
{ 
copy ("$bdrm2", "./pictures/$bdrm2_name") 
or die("Bedroom 2: Could not copy file."); 
echo "Bedroom 2: File $bdrm2_name Uploaded Successfuly<br>"; 
} 
else {echo("Bedroom 2: No file specified Bedroom 2 Picture.");} 

[The_Chancer]

Urm - you did tell it to stop after the first one though if no picture there...

if($mainpic_name !="") 
{ 
copy ("$mainpic", "./pictures/$mainpic_name") 
or die("Main Picture: Could not copy file."); 
echo "Main Picture: File $mainpic_name Uploaded Successfuly<br>"; 
} 
else {die("No file specified.");} // it will stop here if no photo is put in

If you put the error message in a variable and put it out at the end, at least you will be letting the user know that they didn't upload one for that section...

[ihenman]

Thanks...thats makes perfect sense now taht I look @ it I must've just been looking @ it way too long!

[okuto1973]

Plz mark this thread as RESOLVED!!!!!!!