Trouble accessing file in different directory

[basil]

I have a php file in a directory called "photos" and I need to open another file called 0000000A.cgi for reading that is located in a directcory "/cgi-bin/Members" My code is trying to open a file in "photos/cgi-bin/Members/0000000A.cgi"

I get an error that says:
"Warning: file("/cgi-bin/Members/0000000A.cgi") - No such file or directory in /home/www/myserver/photos"

Here is my code:

$fpp=@fopen("$DOCUMENT_ROOT/cgi-bin/Members/$memberfile", "r");

(Memberfile = 0000000A.cgi)
I thought $DOCUMENT_ROOT would take me back to the root dir of my server (website), but it seems to be referencing the cgi-bin dir as a sub directory of the directory "photos" (where my calling php script is located). So, how do I reference the correct file off of my server root directory in my fopen command?

Thanks,
Basil

[SantaGhost]

$DOCUMENT_ROOT should be:

$_SERVER['DOCUMENT_ROOT']

[basil]

Ooops, I tried that and got the following error:

Parse error, expecting 'T_STRING' or 'T_VARIABLE' or 'T_NUM_STRING'

My code now looks like this:

$fpp=@fopen("$_SERVER['$DOCUMENT_ROOT']/cgi-bin/Members/$memberfile", "r");

What's wrong with my syntax now?

Thanks,
Basil

[Merve]

Originally posted by basil
Ooops, I tried that and got the following error:

Parse error, expecting 'T_STRING' or 'T_VARIABLE' or 'T_NUM_STRING'

My code now looks like this:

$fpp=@fopen("$_SERVER['$DOCUMENT_ROOT']/cgi-bin/Members/$memberfile", "r");

What's wrong with my syntax now?

Thanks,
Basil [/B]

Try this:

$fpp=@fopen("{$_SERVER['$DOCUMENT_ROOT']}/cgi-bin/Members/$memberfile", "r");

This might work...I think.

Merve

[basil]

Nope, sorry, now I get the same error as I had before 🙁

Basil

[viper78]

try this

$fpp=@fopen($_SERVER['DOCUMENT_ROOT'] . "/cgi-bin/Members/$memberfile", "r");