include and require help

Mucello

Perhaps I'm making this too difficult. I'm trying to require() a php file in one of my scripts... no problem right? But I want to pass a variable along with it, much like you would in a URL.

I want to require a file called ver.php and give it a parameter.

So for example, if I were going to the page directly via my browser, I would go to ../ver.php?action=whatever

I want to say require 'ver.php?action=whatever' but doing so gives me a fatal error saying the file cannot be opened.

So my question is, how do I pass a variable into an included file?

maxpup979

ummmm---when you include the file, it is kind of like you are adding the code to your existing page--so the variable is visible to the include file.--without having to pass it in--
$a="test";

include "somefile";

$a is now visible to the stuff in somefile (assuming usual rules of scope)

Mucello

Thanks for the reply. That makes sense. What I'm trying to accomplish though is not necessarily pasting the contents from the file, but rather pasting the output from the file. 'ver.php' is its own page with its own output. I just want to get the contents of that output, not the code itself. Does that make any sense?

hermzz

Add the variable before and then it should be able to read it, like maxpup979 said its like pasting the code...

$a = "something";
include(ver.php);

and then in the file ver.php just use the $a variable.