Bah! Getting the URL is just impossible...

Manga27

Ok, this is not supposed to be hard. Anyone run into this problem before?

Assume I have two files:

http://www.testdomain.com/index.php
... and ...
http://www.programdomain.com/program.php

INDEX.PHP

PROGRAM.PHP

echo $_SERVER['PHP_SELF'] . "<br>";

Now, all I want PROGRAM.PHP to do is display the URL that is in the user's address bar... BUT, when I run the program, I get the PROGRAM URL, NOT the URL for the INDEX.PHP file.

In other words, I get:
http://www.programdomain.com/program.php

when I should be getting
http://www.testdomain.com/index.php!

Ok, so I guess PHP_SELF shows you the CURRENT SCRIPT that is running, NOT the URL in the user's address bar. Right? Or is there another way to do it so it shows the right URL?

Any ideas guys? Thanks in advance!

Take care,

... Christopher

HalfaBee

If you want the current script running use

By using a require with a full URL you are running a different URL, but I think you already worked that out.

HalfaBee

Manga27

No, sorry - I must not have been clear...I want to get the parent script (the one that called the current script running) - I guess I should have clarified.

NOT the current script running, but rather the page that called it. (testdomain.com/index.php called programdomain.com/program.php, and I want program.php to output "testdomain.com/index.php", in other words the script that called it.

Hope this clears it up. Thanks.

Weedpacket

There's a lot more information in the $_SERVER[] array than just PHP_SELF (that's why it's an array).

print_r($_SERVER[]) to see.

HalfaBee

$_SERVER will not show anything useful if you use require.

HalfaBee

Manga27

Yes, I understand. I have already printed the entire _SERVER array, and every variable comes up as the program that is running, not the program that originally called it.

There seem to be absolutely no references to this anywhere.

I'm surprised nobody else has run into this problem before. Any other ideas?

Thanks.

Weedpacket

Oh, of course; including the page via a URL; that would make the difference.

The user makes a request to the web server, and the script that runs as a result sends an entirely new request to the web server. There is nothing to indicate to the web server that the two requests have anything to do with each other, so it has no way of knowing that the request-URI of the first request has anything to do with the running of the second request.

Practical upshot is that you'll have to send the request-URI of the first request to the second yourself (I'm assuming that the different domains indicates that you can't just use filenames to include the script). I guess you could attach it to the URL something similar to

require('http://www.programdomain.com/program.php?referer='
. urlencode($_SERVER['REQUEST_URI']));

And then read $_GET['referer'].