preg_replace

Herk

I am trying to run a path "/images/thumbs/." through a filter to yield ".". Please do not give me an RTFM. I have, and for some reason it is too cryptic for me tonight. This pattern syntax is driving me mad.

This is doing the job, but I really don't know why. I'd like to simplify the pattern and understand it, too.

$i = 0;
foreach (glob('images/thumbs/*') as $dirfile) {
	$file = preg_replace("'\i[\/\!]*?[^<>]*?\/[\/\!]*?[^<>]*?\/'si", "", $dirfile);
    echo "".$file." size ".filesize($dirfile)."<br>\n";
	$thumb[$i] = $file;
	$i++;
}

That big long ugly string for the pattern, "'i[/!]?[^<>]?/[/!]?[^<>]?/'si", is absolutely greek to me. I just ripped it off of the manual to see if it would work. Although it works, I prefer to know what I am doing. Please help me.

Thank you kindly,
Herk

TheIceman5

lookie what we have here, 2 posts away on the same damn page, wish people would bother to read and search.

http://www.phpbuilder.com/board/showthread.php?s=&threadid=10257712

Herk

The last post on that thread before my question was posted was just after 4 o'clock, so it was not very high on the list until just before you posted. Also, I did search, and I did not find that thread(perhaps my search tems were not sufficient). I appologize for defiling the forum with another post concerning the same thing.

Thank you though for pointing me in the right direction.

Herk

I got it to work, with the help of that tutorial, using this code:

$file = preg_replace("/.*\//", "", $dirfile);

Thank you for your assistance.

Herk