passing an error message variable to another page

[skdzines]

Okay, I have this code:

<?
//Code returned
$AVSCode="Y:3585460f5bc4f800:YNYM:093250860081744XF3LW 01:";

$Address=substr($AVSCode,19,1);
$ZipCode=substr($AVSCode,20,1);
$CVM=substr($AVSCode,22,1);


if ($Address != "Y"){
	$error.="The Address provided does not match the information on file with your card issuer.<br>\n";
}
if ($ZipCode != "Y"){
	$error.="The Zip Code provided does not match the information on file with your card issuer.<br>\n";
}
if ($CVM == "N"){
	$error.="The code located on the back of the card provided does not match the information on file with your card issuer.<br>\n";
}

//if any errors occur
if ($error){
	header("Location: http://www.whatnott.com/avsFailure.php");
}else{
	header("Location: http://www.whatnott.com/avsPassed.php");
}
?>

If there are any errors, I want the error to be sent to the avsFailure.php page to display all of the errors. How do I get the value in the $error to pass to the next page?

This is the code on avsFailure.php to display the errors:

<?
if ($error) {//if there is any error message, print it to the screen
echo "<table width=550 align=\"center\" div align=\"center\"><br /><font color=red><b>The following problems occurred:</b><br /></font><font color=#000000 size=1>\n"; 
print ("$error"); 
}
?>

It goes to the correct page because there are errors but it won't display them.

Thanks for your help.

[maxpup979]

header("location:yadda?errorinfo=1234");

[skdzines]

okay, that worked. I had to do this:

header("Location: http://www.whatnott.com/avsFailure.php?error=$error"); 

but it is only showing one error. If there are more than one error, it doesn't display the others. It only shows the first one.

Any ideas?

Thanks