Return value from a seconday form

[esteganos]

Hello,

This must be something trivial, but ...

I have a form in a php page, where some fields are text box that must take their values from another form that I open in a new window with javascript. The secondary form contains a select control.

How must I return the selected value to the main form?

I have this code for the secondary form, but then, what happens is that the main forms reopens on the secondary window, not in the original main window from where I called the secondary.

<form name=secondary action=\"gestion.php\" method=\"post\">

If my explanation is not clear, please, let me know

Thanks in advance,

[bad76]

Hi,
i don't understand so well... however:

i think you open a second window and the user select a value.
You need to report this value. I'm rigth?

Well, to do this you can use JavaScript, just accessing any hidden field of primary form trough window.opener object:

<script>
function secondsubmit(x)
{
window.opener.document.primary.comboval.value=x;
window.close();
}
</script>

This little script, called when submit the second form, report the selected value in a field called comboval (is the hidden field in primary form...) and close secondary window.

I hope this help you

[esteganos]

Hi, thanks, that is what i need, but, sorry, i am not trained about working with js on php,

How must i implement that on my code?

This is the code in the secondary form,

how must i call the proposed function so i can use the selected value as the parameter.

<?
print("<form name=secondary method=\"post\">");

$sql_seleccion = "select * from tractoras";
$r_seleccion = mysql_query($sql_seleccion);
print("<select name=tractora size=8>");
while ($f_seleccion = mysql_fetch_array($r_seleccion, MYSQL_BOTH)){
	print("<option value=\"$f_seleccion[id]\">".$f_seleccion[matricula]."</option>");
}
print("</select>");
print("<input type=submit name=validar value=Validar>");
print("</form>");

?>

Thanks again

[bad76]

Originally posted by esteganos
print("<input type=submit name=validar value=Validar>");

This is to hack, just change to:

<a href="#" onclick="secondsubmit(document.secondary.tractora.value); return false;">sumbit</a>

This call the function i wrote.

If you want use submit button try this:

<? 
print("<form name=secondary onsubmit='secondsubmit(document.secondary.tractora.value); return false;'>"); 

$sql_seleccion = "select * from tractoras"; 
$r_seleccion = mysql_query($sql_seleccion); 
print("<select name=tractora size=8>"); 
while ($f_seleccion = mysql_fetch_array($r_seleccion, MYSQL_BOTH)){ 
print("<option value=\"$f_seleccion[id]\">".$f_seleccion[matricula]."</option>"); 
} 
print("</select>"); 
print("<input type=submit name=validar value=Validar>"); 
print("</form>"); 

?> 

i hope this help.
see you