Functions &amp; Buttons

Functions & Buttons

enickols

//Select client information for display
if($u == 'tslack')
{
echo "<HTML><HEAD><BODY><H1><CENTER>Tom Slack</CENTER></H1><BR>";
echo "<HTML><FORM NAME=slackform>";
echo "<CENTER><TABLE BORDER=2>";
echo "<TR><TD ALIGN=center><SELECT NAME=SlackSemester><option> </option><option>Fall</option><option>Spring</option><option>Summer</option></TD>";
echo "<TD ALIGN=center><SELECT NAME=SlackYear><option> </option><option>2003</option><option>2004</option><option>2005</option></TD></TR></CENTER>";
echo "<INPUT TYPE=submit NAME=submit VALUE='Get Data' ONSUBMIT='slack()'>";

}

$info = mysql_db_query($db, $sql_client)
or die("Invalid query: " . $sql_client . "<p>" . mysql_error());

function slack()
{
$sql_client = "SELECT * FROM formdata WHERE Instructor = 'name' ";
}

The variable $u is checked to see which person has logged in. For example, tslack as logged in. I want to be able to press a button and have his data displayed within the HTML window. Can I just call this function from onSubmit and have it run when the user clicks the button? As you can see I also have to drop down menus on the form. Once I figure out how make this function run I'll pass the drop down values as paramaters.

All in all, how can I make a function run through clicking a button?

OhLordy

No, you can't. PHP is a server side language. OnSubmit and things like that only work with client side languages such as javascript. In order to pass the info to php you will have to submit and reload the page.
HTH
Rob

enickols

So what I need to do is something like this:

if($u == 'tslack')
{
echo "<HTML><FORM NAME=slackform METHOD=POST ACTION=file.php>";
echo "<INPUT TYPE=submit NAME=submit VALUE='Get Data' >";
}

Thanks!