Two Variables inside a variable name......

[austinderrick2]

$database1 = "test";
$database2 = "test2";
databasenumber = 2;
for ($i = 1; $i <= $databasenumber; $i++) {
          $databasename = $database$i;
}

This is throwing an error but you can tell what I'm trying to do with the script. Does anyone know how to get this to work?

[LordShryku]

$databasename = $database.$i;

Need the . for seperation

[iceraider]

lol you missed it lord

databasenumber = 2;

needs to be

$databasenumber = 2;

[LordShryku]

Yeah, I think the lack of sleep is starting to take over. Too much to do, ya know?

[austinderrick2]

Well that was just an example 😉 I have the $ in my script. Thanks the . thing worked.

[superwormy]

You migth be better off using an array... just a thought.

[austinderrick2]

I dont know how to use arrays...

[LordShryku]

Not real hard. Just read up on it, and ask questions when ya have them 🙂