[Resolved] Dropping a Database in MySQL

[DeadFly]

Here is what I have, but she ain't working !
I tried looking for a command like mysql_create_db(), which would do the job, but I ended up trying using mysql_db_query().

$Query="DROP DATABASE $_POST['SQLDBName']";
if (mysql_db_query($_POST['SQLDBName'], $Query)) {
    echo'<img src="img/ohno.gif" width="15" height="15"></td></tr>';
}else{
    echo'<img src="img/ohno.gif" width="15" height="15"><br>'.mysql_error().'</td></tr>';
}

Basically what happens right now is that I get a time out.
Thanks in advance for any help !
🙂

[PHPGuru2]

Have you tried using mysql_drop_db()??

[DeadFly]

No I didn't try mysql_drop_db().
I actually used my code that I have below, but I dropped the ' ' around $POST[SQLDBName] in the $Query.

$Query="DROP DATABASE $_POST[SQLDBName]"; 
if (mysql_db_query($_POST['SQLDBName'], $Query)) { 
    echo'<img src="img/ohno.gif" width="15" height="15"></td></tr>'; 
}else{ 
    echo'<img src="img/ohno.gif" width="15" height="15"><br>'.mysql_error().'</td></tr>'; 
}

Thanks for the help.
I'll try switching my code over to mysql_drop_db() to maybe save some lines of code.