Quick and dirty method for adding 2 hours to a datetime

tiburblium

Hi all, im looking for a quick and easy way to add 2 hours to this string

$dateout = strftime("%m/%d/%Y %H:%M:%S" ,strtotime($datein));

any ideas?

ive been messing around with time stamps and conversions but am not having any luck thus far.

Thanks in advance!

njm

$dateout = strtotime('+2 hours', $datein);

hth, njm

tiburblium

Thanks i think im getting closer, mabey im doing something completely wrong here but I am getting no output when I use that string. The dates are datetime that are coming directly out of a mysql database so I am trying to add 2 hours to them and then reformat them:

$dateout = strtotime('+2 hours', $datein);

		$datefinished =  strftime("%m/%d/%Y %H:%M:%S" ,strtotime($dateout));

print "$datefinished";
Any reason why this doesn't work? it seems like it should..

njm

You're using strtotime() incorrectly in your penultimate statement - you don't need it:

$dateout = strtotime('+2 hours', $datein);
$datefinished = strftime("%m/%d/%Y %H:%M:%S" ,$dateout);
print $datefinished;

hth, njm

tiburblium

When I try $dateout = strtotime('+2 hours', $datein);
$datefinished = strftime("%m/%d/%Y %H:%M:%S" ,$dateout);
print $datefinished; my time is showing up as:

12/31/1969 18:33:23

However when I change the hours to say +4 hours it is reflected in the time. so +4 hours would equal

12/31/1969 20:33:23

Ive been looking at the time functions, should I turn the date into a unix timestamp, add 7200 seconds, then format it with mktime?

ive been trying to do this but havent had any success, all the examples ive found are way more complicated then what im trying to accomplish.