Drop Down Menu Question

[Sharif]

I need to do this:

Have a drop down menu where the initial selection is: SELECT LETTER.

The choices are:

A
B
C
X
Y
Z

I would like to do this: Say the user picks A, but the form I created requires them to enter missing information, how would I get the drop down to have A selected instead of SELECT LETTER.

[sarahk]

I have code like this

function echoSelect($name, $value, $choices)
  {
    $output = "<select name='{$name}'>";
	foreach( $choices as $k => $v)
	{
	   $output .= "<option value='{$v}'";
	   if ($value == $v) $output .= ' selected';
	   $output .= ">{$k}</option>";
	}
	$output .= '</select>';
	echo $output;
}//echoSelect

//so your code would call:

echoSelect('dropName', $dropName, array('A','B','C','X','Y','Z'));

[Sharif]

Are there any alternative methods?

[maxpup979]

You could use javascript to control it--but the method sarahk suggested is tried and ture--works very well

[Sharif]

I would have a lot of typing to do if I used that function, since the drop down would contain a list of the countries of the world... no other solutions?

[Sharif]

Found a solution:

<select name="country" id="country">
                <option value="" <?php if (!(strcmp("", $_POST['country']))) {echo "SELECTED";} ?>>Select Your Country
	<option value="Albania" <?php if (!(strcmp("Albania", $_POST['country']))) {echo "SELECTED";} ?>>Albania</option>
	<option value="Argentina" <?php if (!(strcmp("Argentina", $_POST['country']))) {echo "SELECTED";} ?>>Argentina</option>
	<option value="Australia" <?php if (!(strcmp("Australia", $_POST['country']))) {echo "SELECTED";} ?>>Australia</option>
</select>