[Resolved] [Resolved] Variable variables

furious5

Can anyone help me, I am trying to output an array with 52 date fields.

Basically I what to suffix a variable with an incremented number, does anyone know how I can do this?

e.g $date.$i

I have tried this but without any success.

tekky

Somebody didnt Search

Theres a topic with this exact title almost every week.....

mrhappiness

some coude would be useful

$a='fu';
$b='bar';
$fubar='mrhappiness is great';
echo ${$a.$b};

something like this?

furious5

Hmm that is almost what I am after.

To change tack ever so slightly, I have a string called $key which is an incremented value - contained within the string is the value date1 therefore it is incremented so I get values date1, date2, date3 etc.

Basically the easiest way would be for me to turn this value in to a string in its own right. So I could have $date1, $date2, $date3. My only problem is I don't know how to do this on the fly given I have 52 fields!

Any ideas?

tekky

Originally posted by tekky
Somebody didnt Search

Theres a topic with this exact title almost every week.....

lets try this one more time... actually LOOK at the link this time though...

for example this link http://www.phpbuilder.com/board/showthread.php?s=&threadid=10227603&highlight=variable+AND+variables

has many examples of VARIABLE VARIABLES

and low and be hold....

http://us4.php.net/manual/en/language.variables.variable.php

even the online documentation has "variable variables" when you search for them...

and.... http://us4.php.net/manual/en/control-structures.for.php

for how to do it "on the fly"

furious5

I did read through some of the links initially, but couldn't find a good example of what I was trying to achieve.

I've read through them in some detail, but still have a few questions I was hoping someone could help me with.

It seems that I can use a variable variable providing I echo the value, however what if I want to use the new variable to store a value?

Here is what I am wanting to do:

$date{$i} = $dateArray[$key];

Obviously this doesn't work, and I can't echo the statement as I don't want it printed on screen. 😕

furious5

Resolved

Wasn't using the $$ notation.

furious5

Arrggh

Still struggling with this.

I can get the variable variable to iterate through all the values as required.

However it seems to fall over once it has got the value from the first item within the array.

Can anyone help me with this, and perhaps suggest why this is the case? Providing it has iterated through and created individual variables each should now have there own string contained within them. But this isn't happening

$i = 1; // Counter

foreach($_POST as $key=>$val){ 
    $dateArray[$key] = preg_replace( '#([0-9]+?)/([0-9]+?)/([0-9]{4})#','3-1-2',$val); 


	$key = "date".$i; // Array Key
	$val = $dateArray[$key]; // Get value from array
	$$key = $val; // Pass value to variable variable
	echo "$$key".":".$$key; // output values


$i++; // Increment Counter

}