Insert URL

stageleft

I am trying (so far unsuccessfully) to figure out how to call a URL into a page.

Page layout is accomplished via css and I would like to have a web page from a different part of the site called into the content area of the page.

If I use $filename = "url of page" -or- "path/to/php/page/to/be/displayed/" all I get is the page code.

Is there a way to call one web page into another other than using something like an iframe, something I want to avoid.

Thanks

theeper

use include() or require()

slaya

Im not sure what you mean so im going to try to guess..

If you want it so if the url is http://domain.com?page=home it displays home and if its http://domain.com?page=news it displays news than use a switch statement..

switch ($_GET['page']) {
  case 'home':
    //home content here
  break;

  case 'news':
    //news content here
  break;
}

drag0n

I think theeper meant to use include('filename.php') or require('filename.inc.php') to include the content where u have
//home content here
etc..

stageleft

I'll try a more full explanation, that first one was a bit sparse

I have a blog setup in the directory /pmachine where a 3 col blog layout is controlled by css.

I'd like to wrap a php/MySQL discussion forum that is installed in /pmachine/forum/ into the blog by somehow having /pmachine/forum/index.php called into the content column div of the blog page at /pmachine/weblog.php

include('forum/index.php') in the content div didn't work as the forum script couldn't locate other component information that it was looking for that lives in (for example) /pmachine/forum/include.

Somewhere as part of the include I assume I need to set additional information to allow everything in /forum (and below) to be found so that it all works properly.

Thanks

Sharif

Are you trying to include the current url in the browser in a variable? Sort of like:

If the url is: http://www.phpbuilder.com/board

You want the variable:

$url = 'http://www.phpbuilder.com/board;

or whatever the url is?