[Resolved] concat the actual string name

skeetley

Hi everyone,

I am passing a variable, $station, to a loop. For this example lets say $station="ALPHA";

In my loop I do a bunch of stuff, including putting a variable in $data. For this example $data wil be equal to 12.

Now I since this loop gets run many times over, I want to store this in a new variable called $ALPHAdata so that $ALPHAdata=12. ALPHA is of course whatever station name gets passed and I want to add the data to the string name. How do I do this?

I have tried $station.data = $data. I have also tried $station."data" = $data and again it doesn't work.

Any help would be greatly appreciated.

Shuriken1

I'm not quite sure what you are tryin to acheive but from what I understand you are trying to add the data var onto the station var, which in this case would produce "ALPHA 12". If that is what you are tryin to do you can do this:

$station .= " $data"; //Note the space.

That will give you "ALPHA 12" in your station var.

Hope that helps.

Shuriken1.

skeetley

Shuriken1,
Close but not quite what I am trying to do.

I'll try and explain better if I can. I have several stations, say ALPHA, BETA, CAPPA, etc. Each time the loop is run a variable is put in the string $datastring. So when the loop runs for ALPHA, maybe datastring is 34, when BETA runs maybe datastring is 12. Before this value is lost, I want to save it to a new variable that includes the station name. I want this new variable to be whatever the station name is and the word, say value. So at the end of the loop iterations I will have ALPHAvalue=34, BETAvalue=12, CAPPAvalue=....

Now $station=$datastring would make ALPHA=12. I want to add the word value onto the string so that I get ALPHAvalue=12.

skeetley

Hmm, that last post gave me an idea and it seems to work. Maybe not the best way, but working is working.

To carry on that last example I made a dummy string $valuestring="value".

Then I made $station.$valuestring=$datastring

And there you go.

Weedpacket

${$station.'data'}

PHP has to know where the name ends. Leaving off the braces is ambiguous.