[Resolved] Date simple question

[scialom]

Hello all,

I have 2 vars with dates:

$a = "2003-11-26";
$b = "2003-11-25";

I try to do this:
$Sum = $b-$a;

But I get 0.

How can I do it?

thanks,
Assaf

[tuf-web_co_uk]

if you just wanted to output the number of days between the two dates then you should use something like this

remember: variable with quotes around it acts as as string, and therefore not a number, which is probably why your script returned 0

<?

$a = date(2003-11-26); 
$b = date(2003-11-25); 

$Sum = $b-$a;

echo $Sum;
?>

this should return 1 it did on my com

[tserbis]

tuf-web.co.uk

$a = date(2003-10-30);  

$b = date(2003-11-01);  

$Sum = $b-$a; 

echo $Sum;

this return 28 on my com 😃

[tserbis]

scialom

$d1 = '2003-10-30';
$d2 = '2002-10-30';

echo $days = abs(strtotime($d1) - strtotime($d2)) / 3600 / 24;