help in placing PHP code

lisawebs

I'm not understanding why page behaves different
depending on where I place the PHP code.

Sometimes, when refreshing a page with data brought by PHP
the data stays there, sometimes not.

is there a command to make PHP behaves as if it where
the first page loading ?

is the same for localhost or remote server?

Thanks

BuzzLY

Can you provide some examples? I'm not really sure what you are talking about.

lisawebs

after 16 hours in the pc.. nonstop,
I can't understand.

when retrieving data rows,
if the php code is above the <form> code
once the data comes, even refreshing the page
(under localhost) the data stay there.
when placing the code below, then it works fine.
you'll see I'm not good on this,
each time I load the following page,
it writes a record, before doing anything,
I don't understand why the variable opcode (in the form)
is always set up, even the first time I load the page...
I'm working locally (under XP).

I'm not getting the philosophy of PHP.
When it calls itself (SELF), I suppose it sends the page data
to the server, executes (there) the php logic
and returns...
now, why the document. data are still there?
how can I control (from php) when to reset document. data
or when keep them...

sorry for so much buble....

this is abreviated

<?php

$msg = "";

if (isset($_POST['opcode'])) {
if ($senal > 3 or $senal < 1){
$senal = 0;
} else {
$senal = 1 ;
}
}
// I don't know why $senal is always 1
//.....
if ($senal = 1){
$dbcnx = @mysql_connect("localhost");
if (!$dbcnx) {
echo( "<P>Unable to connect to the " .

"database server</P>" ); exit(); }

if (! @mysql_select_db("sia_acidentes") ) {
echo( "<P>Unable to locate the " .
"database</P>" ); exit(); }
}

if ($senal == 1){
// pass document.data to php variables
$reg_data = $_POST['reg_data'];
//....
}

if ($senal == 1){
// issue command to update database
//$sql = "INSERT sia_registro SET reg_data = '$reg_data' ,

//......
$result = mysql_query($sql);
if (!$result) {

echo("<P>Error performing query: " .

mysql_error() . "</P>");

$senal = -1;
$msg = "transaction failed" ;
} else {
$senal = 9;
$msg = "data updated";
$opcode = 0;
}

}

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD><TITLE>SIA</TITLE>

// called when user click the button to update
function checkdata(){
if (ok){
document.caso.opcode.value = "1"

document.caso.submit()
}
}
</script>
</head>

<BODY>

// writes all the hidden input field to store values for the
// transaction
function dataforphp(){
document.write('<form name=caso ACTION="<?php echo($PHP_SELF); ?>" METHOD=POST>')
document.write('<input type=hidden name=opcode value="">')
//.....
}

</script>

</body>
</html>

lisawebs

I found out last topic, now,
what about writing Jscript with php?

echo("<script>");
echo("alert('hello')");
echo("</script>");

works fine, but inserting a line like the following
doesn't work:

echo(" var a = $variable ");

why????

Brendan_Nolan

Originally posted by lisawebs
I found out last topic, now,
what about writing Jscript with php?

echo("<script>");
echo("alert('hello')");
echo("</script>");

works fine, but inserting a line like the following
doesn't work:

echo(" var a = $variable ");

why????

It would be replacing $variable. Probably with nothing. Either go

echo(" var a = \$variable ");

echo(' var a = $variable ');

lisawebs

CASE A - $variable = 1

echo(<script> \n var a = $variable \n alert(a) \n </script>");

shows the value,
if $variable = "abc" ,then the above code gives an error unless the variable abc is defined in Jscript context,

CASE B - $variable = "abc"

echo(<script> \n var a = '$variable' \n alert(a) \n </script>");

shows abc as a string