Why this error?

[Elhombrebala]

  

<?php
//page2
session_start();
if (session_is_registered('usuario')){
}
else{
header("Location: acceso6.html?errorusuario=si");
}
$session= session_id();
$base="";
$conexion=mysql_connect("","","");
mysql_select_db($base,$conexion);
$pegar2 = "SELECT Inmo FROM Sesiones WHERE Sesion='$session'"; 
$row = mysql_fetch_array($pegar2); 
$Inmo = $row["Inmo"]; 
?>

ERROR:


Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /chs/p1/costa4seasons.com/home/html/panelcontrol.html on line 13

[LordShryku]

You never use mysql_query()

[Elhombrebala]

OK; I have tried like this, but I've got NO error message, but echoing $Inmo gives nothing.

<?php
//page2
session_start();
if (session_is_registered('usuario')){
}
else{
header("Location: acceso6.html?errorusuario=si");
}
$session= session_id();
$base="";
$conexion=mysql_connect("","","");
mysql_select_db($base,$conexion);
$pegar2 = "SELECT Inmo FROM Sesiones WHERE Sesion='$session'";
mysql_query($pegar2); 
//$row = mysql_fetch_array($pegar2); 
$Inmo = $row["Inmo"]; 
?>

[LordShryku]

$pegar2 = "SELECT Inmo FROM Sesiones WHERE Sesion='$session'";
$result = mysql_query($pegar2); 
$row = mysql_fetch_array($result);
$Inmo = $row["Inmo"];