[Resolved] Putting parsed file in $variable

jek

Hi there!

Is there any way to put the result of a parsed file into a variable?

Here's what I'm trying to do:

$text = (include "hits.php");
$text = preg_replace( "/( ){1,}/", "_", $text );
echo "$text";

But it seems like the first line doesn't put the parsed file hits.php into the $text variable, but instead just include hits.php...

This is just a simplified version of my script, I will be using more complicated regular expressions, but you get the idea...

Thanks in advance / jek

maxpup979

it sounds like you are trying to open, and read a file, right?....try:

// get contents of a file into a string
$filename = "/usr/local/something.txt";
$fd = fopen ($filename, "r");
$contents = fread ($fd, filesize ($filename));
fclose ($fd);

jek

Originally posted by maxpup979
it sounds like you are trying to open, and read a file, right?

Not really, but close...

I want the server to parse a file, and instead of echoing it directly to the browser I want the result put in a variable...

Let's say the file hits.php looks like this:

<?
for ($i = 0; $i < 10; $i++) {
$text .= "$i ";
}
?>

If I just open and read the file and put it into the variable $text, $text will look like this:

<? for ($i = 0; $i < 10; $i++) { $text .= "$i "; }?>

But I want $text to look like this:

0 1 2 3 4 5 and so on...

superwormy

To get the contents of a parsed file into a variable... you can do one of two things.

<?php

ob_start ();
include ("myfile.php");
$parse_file_contents = ob_get_contents ();
ob_end_clean();

// do whatever with $parsed_file_contents
print ($parsed_file_contents);

<?php

$fp = fopen ("myfile.php", "r");
$raw_contents = fread ($fp, filesize ("myfile.php"));
fclose ($fp);

ob_start ();
eval (" ?> " . $raw_contents . " <?php ");
$parsed_contents = ob_get_contents ();
ob_end_clean ();

// do whatever with $parsed_contents

jek

Thanks a lot mate, it's working great.

/ jek