PHP BUG in checking array values?

edrugtrader

if(($current_value[7] != 1) && ($current_value[7] != 0)) {
   $employees_to_report[] = array($current_key, 7);
   echo "employee $current_key has the value ".$current_value[7]." for month 7<br />";
   echo "<pre>";
   print_r($current_value);
   echo "</pre>";
}

as i'm looping through an array full of numbers, this code keeps getting executed even though the value of $current_value[7] is 1. here is the output. i can't understand this at all.

output to follow: -------------------------------------

employee 382 has the value 1 for month 7

Array
(
[1] => 0.67
[2] => 0.67
[3] => 0.67
[4] => 0.67
[5] => 0.67
[6] => 0.67
[7] => 1
[8] => 1
[9] => 1
[10] => 1
[11] => 1
[12] => 1
)

edrugtrader

i have already tried string comparison as well and it still has the same results.

even switching the code to run with this if statement still gets through:

if((($current_value[7] < 1) && ($current_value[7] > 0)) || ($current_value[7] > 1)) {

Weedpacket

The code you've posted works for me;

$current_value=Array
(
1 => 0.67,
2 => 0.67,
3 => 0.67,
4 => 0.67,
5 => 0.67,
6 => 0.67,
7 => 1,
8 => 1,
9 => 1,
10 => 1,
11 => 1,
12 => 1
);
if(($current_value[7] != 1) && ($current_value[7] != 0)) {
   $employees_to_report[] = array($current_key, 7);
   echo "employee $current_key has the value ".$current_value[7]." for month 7<br />";
   echo "<pre>";
   print_r($current_value);
   echo "</pre>";
}

Does it for you? If so, the problem went away when you edited the code for posting.