Will this cause some trouble?

Elhombrebala

Will this echo cause any trouble because of the slash and chracters inside ""?

if ($row['ene1t']!=0) echo{"(3-1-2004/10-1-2004)";}

Weedpacket

Try it and see...?

(The main character you have to watch for in double-quoted strings is the backslash . More information on double-quoted strings)

Elhombrebala

Very nice from you.
I have already tryed and I get an error, but I would like to know if it comes from there or not.
It is not too much job for you to answer for nothing?

Weedpacket

Ah, well, you should have said (and said what the error was). Lose those {}. I just answered the question you asked.

Elhombrebala

Why this is storing nothing on my table?
For me seems to be ok.

<?php
session_start();
if (session_is_registered('usuario')){
}
$Sesion = session_id;
$conexion=mysql_connect('', '', '');
mysql_select_db("",$conexion); 
$sql = "INSERT INTO Reservas ( Ref, ene1t, ene2t, ene3t, ene4t, ene5t, feb1t, feb2t, feb3t, feb4t, feb5t, mar1t, mar2t, mar3t, mar4t, mar5t, abr1t, abr2t, abr3t, abr4t, abr5t, may1t, may2t, may3t, may4t, may5t, jun1t, jun2t, jun3t, jun4t, jun5t, jul1t, jul2t, jul3t, jul4t, jul5t, ago1t, ago2t, ago3t, ago4t, ago5t, sep1t, sep2t, sep3t, sep4t, sep5t, oct1t, oct2t, oct3t, oct4t, oct5t, nov1t, nov2t, nov3t, nov4t, nov5t, dic1t, dic2t, dic3t, dic4t, dic5, Sesion)".
"VALUES ('$Ref', '$ene1t', '$ene2t', '$ene3t', '$ene4t', '$ene5t', '$feb1t', '$feb2t', '$feb3t', '$feb4t', '$feb5t', '$mar1t', '$mar2t', '$mar3t', '$mar4t', '$mar5t', '$abr1t', '$abr2t', '$abr3t', '$abr4t', '$abr5t', '$may1t', '$may2t', '$may3t', '$may4t', '$may5t', '$jun1t', '$jun2t', '$jun3t', '$jun4t', '$jun5t', '$jul1t', '$jul2t', '$jul3t', '$jul4t', '$jul5t', '$ago1t', '$ago2t', '$ago3t', '$ago4t', '$ago5t', '$sep1t', '$sep2t', '$sep3t', '$sep4t', '$sep5t', '$oct1t', '$oct2t', '$oct3t', '$oct4t', '$oct5t', '$nov1t', '$nov2t', '$nov3t', '$nov4t', '$nov5t', '$dic1t', '$dic2t', '$dic3t', '$dic4t', '$dic5t', '$Sesion')"; 
$result = mysql_query($sql) or die(mysql_error().'<p>'.$sql.'</p>');
$result2 = mysql_query("SELECT * FROM Reservas WHERE (Sesion='$Sesion')", $conexion); 
while($row = mysql_fetch_array($result2))  {
?>

Weedpacket

The only thing I can see wrong with it is the line

$Sesion = session_id;

which should of course be

$Sesion = session_id();

but you ought to be getting an error from that ... oh, right, that would only be if your error reporting is not set to ignore notices.

If you look at the table I think you'll find that your Sesion field contains the word 'session_id'.

Urk; sixty-five hours without sleep. That's not good.......