variable within echo statement table does not work

[jkatcher]

I get a parse error w/ this code. Everything was running smoothly till I put in the $name variable as another <td> in the first table. I tried every permutation of single and double quotes as well as semi-colons, but none seem to work! Do you have any suggestions? Thanks.

echo '
<br>
<center>
<table width="200" cellpadding="0" cellspacing="0" border="0">
<td>Name:</td>
<td>$name</td>
</table>
<table width="200" cellpadding="0" cellspacing="0" border="0">
<td>Name:</td></table>
<table width="200" cellpadding="0" cellspacing="0" border="0">
<td>Name:</td></table>
<table width="200" cellpadding="0" cellspacing="0" border="0">
<td>Name:</td></table>
</center>';

[LordShryku]

Are you sure the variable's set?

[mrhappiness]

if you had made use of the php tags you surely would have noticed a difference betwenn

echo 'some '.$var.' thing';

and

echo 'some $var thing';

hth

if you use ' as delimiter four your string, php outputs the text "as is" without looking for variable names and echoing their value(s) which makes it a bit faster than using " as delimiter

[jkatcher]

yes, the variable is set. thank you, now it is working.

i used '.$var.' and it's fine. thanks.

j