preg match all

ligraci

Hi,
I have this text:
var namevar = new Array("aaa","bbb","ccc");
var namevar2 = new Array("ddd","eee","fff");
var namevar3 = new Array("ggg","hhh","iii");

How can I obtain an arry like this using preg_match_all?
array(array("aaa","bbb","ccc"), array("ddd","eee","fff"), array("ggg","hhh","iii"));

Thanks

AstroTeg

What is your ultimate goal? What is the string you wish to match against?

ligraci

I need that every string starting with array(" and ending with "; go into an array. There should be 3 strings corresponding to my request.

AstroTeg

Hmm... Have you thought about using eval()?

In theory (and if I read your post correctly), you will have strings looking like:

'array("txt1", "txt2", "txt3")'

You could just:

$mystring = 'array("txt1", "txt2", "txt3")';
$myarray = array();
eval('$myarray = ' . $mystring . ';');
// $myarray should now contain the array data

That code might work - I haven't tested it so I'm not 100% sure. Make sure in the eval line you use single quotes for '$myarray = '. If you use double quotes, PHP will swap in the value of $myarray which isn't what you want here.

I'm not sure if this does what you're looking for...

ligraci

This is the next step. But I need to get my array from the original text using preg_match_all.
It should read the text until the array(" and put it in a new array.
I thought something like this but I don't know if it si correct (or better I don't think it correct because the result is not what I'm looking for...)

preg_match_all("/Array(\"(.*?)\");/s", $text, $array);

AstroTeg

What I'd predict you get back is the contents of Array() so $text should contain: txt1", "txt2", "txt3 - from the looks of it. Maybe you can verify that.

If this is true, then this might work:

preg_match_all("/Array(\"(.*?)\",\"(.*?)\",\"(.*?)\");/s", $text, $array);

Only problem here is you're stuck to only using an array with 3 elements. If you're array had a different number of elements besides 3, I'd think you'd have to get into recursive regular expression matching which I've read about but I've never tried (looks ugly and there's usually another way around the solution).