preg_match_all ???

ice_berg16

$str = "[02:55.57][01:04.94]some word";
$reg ="/([\d{2}:\d{2}.\d{2}])+/i";
preg_match_all($reg, $str, $out);
print_r ($out[1]);

i think this will be output like this;
0 => [02:55.57]
1 => [01:04.94]

but it in fact it output this
0 => [01:04.94]

i don't know its reason
if i want get the first result ,how should i write the $reg?

planetsim

Although Regex is my worse thing in programming i think this may work for you


$str = "[02:55.57][01:04.94]some word";
$reg ="#(\[\d{2}:\d{2}.\d{2}\])#i";
preg_match_all($reg, $str, $out);

ice_berg16

i want to know why what i think is wrong?

i hope someone can explain this to me

pyro

There are a few problem, but this should fix it:

$str = "[02:55.57][01:04.94]some word";
$reg ="/(\\[\\d{2}:\\d{2}\\.\\d{2}\\])/i";
preg_match_all($reg, $str, $out);
print_r ($out[1]);

pyro

Oh, and the problems were the unescaped . in the regex (a . is a special character). That wasn't a big problem, but could have led to problems. The other, and bigger one, was the + at the end. The + tells it to match one or more of the previous, which means it would only match the last one.

ice_berg16

$str = "[02:55.57][01:04.94]some word";
$reg ="/([\d{2}:\d{2}.\d{2}])/i";
preg_match_all($reg, $str, $out);
print_r ($out[1]);

now i want the follow result

out[1]

0 => [02:55.57]
1 => [01:04.94]

out[2]

0 => some word;

how should i do ,notice the [02:55.57] may be not 2,or 3,or more