echo $user

[leetcrew]

$email = '[e-mail]';
$domain = strstr($email, '@');
print $domain; // prints @example.com

how to print the user?

[LordShryku]

$user = substr($email,0,strpos($email,'@'));

[laserlight]

$email = '[e-mail]';
$email_parts = explode('@', $email);
$domain = $email_parts[1];
$user = $email_parts[0];

[leetcrew]

thanks for both of you 😉

[leetcrew]

It works but my goal is to get the filename name and the extension name.

$filename = "TESTING.ZIP";
$name = substr($filename,0,strpos($filename,'.'));
$ext = substr(strrchr($filename, '.'), 1);
echo "<h1>" .$name . "." . $ext;

works fine

$filename = "TESTING.TAR.GZ";
$name = substr($filename,0,strpos($filename,'.'));
$ext = substr(strrchr($filename, '.'), 1);
echo "<h1>" .$name . "." . $ext;

the script returns "TESTING.ZIP" only.

🙁

[LordShryku]

<?php
$filename = "TESTING.TAR.GZ";
$name = substr($filename,0,strpos($filename,'.'));
$ext  = substr($filename,strpos($filename,'.'));
echo "<h1>".$name.$ext;
?>

No need to manually echo the . using this

[leetcrew]

it works perfectly. thanks! 😉