[Resolved] function argument coding?

[leatherback]

Hi,

I have this function declaration (processing scripts left out):

function checkvar($var, $default, $type)
  {
  switch($type)
   {
    case 1:  // integer code
    break;

case 2: // text user input : prevent malicious code from running
break;
   }

  return $var;
  }

Which I call:

$action = checkvar($_POST[action], 1, 1);

In the output I get this error message:

Warning: Missing argument 2 for checkvar() in ****/checkvar.php on line 3

Warning: Missing argument 3 for checkvar() in ****/checkvar.php on line 3

where line 3 is the function declaration line.

What am I doing wrong in this coding?

Thanks!

J.

[AstroTeg]

The code you posted is fine and works by itself. I'm thinking you may have a punctuation issue somewhere. Possibly a mismatch of '{' or '}' or maybe even '(' or ')' (although PHP is pretty good about complaining about parenthesize mismatches).

[leatherback]

ehm..
Yeah..

Found it..
One stupid include further down the page, which uses the old call for the function, before extending it..

-- Red starts to crawl from his neck to his face. Shame all over.. --

Thanks / sorry for the trouble,

J.