appending two variables together ???

byte_me

I am new at PHP and trying to append two variables (which both contain text and then truncate them to 10 characters (from the front)

I have searched the forums/manual and tried with ; without; and various other permutations.

Can any one tell me why I cannot get the variables to take the value on the right side of the equasion? I want the $membershipID to be an amalgamation of $firstName and $lastName and then truncate after the first 10 characters

Here is the bit of the script:

<?PHP
empty($FirstPass) ? # First pass if empty
ShowForm() : # Display the form

$result = $firstName$lastName;
$membershipID = array_slice ($result, 0, 10);

ShowResults ($firstName, $lastName, $username, $password, $handicapStart, $emailAddress, $county, $clubName, $result, $membershipID);

exit;
?>
<?php

function ShowResults ($firstName, $lastName, $username, $password, $handicapStart, $emailAddress, $county, $clubName, $result, $membershipID){echo "These are the details you entered. Please ensure they are correct and click CONFIRMED or user the browsers BACK button to re enter the correct data
 Name = $firstName $lastName Username = $username 
Password = $password 
Current Handicap = $handicapStart 
Your Email Address = $emailAddress 
County of Home Club = $county 
Club Name = $clubName

$result 
$membershipID

<UL>\n";

#foreach ($GLOBALS as $Key=>$Value){
#echo "<LI>\$GLOBALS[\"$Key\"]=$Value\n";

} # End of foreach ($GLOBALS as $Key=>$Value)

echo "</UL>\n";
} # End of function ShowResults

leatherback

Hi,

First off.. Add some structure to your code.. Linebreaks, indenting etcetc
second.. Use the PhP tages of this forum when inserting code

third: assuming this is your problem:

$result = $firstName$lastName;

replace with:

$result = $firstName.$lastName;

fourth: mark this thread as resolved if this solves the problem (See link below)
J.

ClevaTreva

The problem with being new to a language is that you need to know the names of the functions before you can look them up!

I suspect what you want to do is to concatenate the strings.

Let's assume you have these strings:

$a
$b
$c

If $c=$a plus $b you can write it 2 ways:

$c = $a.$b;
(the period is the concatenate function)
or
$c = "$a$c";

if you want to add $b to $a and store the answer in $a, then this is shorter:

$a .= $b;

Trevor

byte_me

Firstly Apols for not using the PHP tagg, didn't realise it was there.
Although pretty code is great to have
an instruction per line usually will suffice.

To clevatreva please see below I did one of your options.
To leatherback, tried yours and same problems

The script I posted and specifically (on line 34)

$result = $firstName$lastName;

gives the error :
Parse error: parse error in /home/shopping/public_html/golf/newaccount2.php on line 34

It doesn't matter whether I put in a . or not between the variables.

What I want to do is to have the $result be equal to $firstName, plus $lastName and then put 1st 10 characters into $membershipID so I can shove it in a MySql DB

I am used to perl and don't usually have probs adding vars but it doesn't seem to like it

leatherback

Hi,

line 34.. Is that the line with concenating? Must be:
The last line of code before it has a : instead of a ;

ps: The comment sign for php is actually // or
/
...
/
Don't think hash works (??)

byte_me

OK got a bit further: threw it into a function...................

 <?PHP
  #empty($FirstPass) ? # First pass if empty
    ShowForm();      # Display the form
	MakeID ($firstName, $lastName, $results, $membershipID);
    ShowResults ($firstName, $lastName, $username, $password, $handicapStart, $emailAddress, $county, $clubName, $result, $membershipID); 


exit;
?>

<?php
function MakeID ($firstName, $lastName, $results, $membershipID){
$r = $firstName.$lastName;
$membershipID = array_slice ($r, 0, 10);#line 44
}
?>

Warning: First argument to array_slice() should be an array in /home/shopping/public_html/golf/newaccount2.php on line 44

what does the error message imply re arrays?

LordShryku

Originally posted by byte me

<?php
function MakeID ($firstName, $lastName, $results, $membershipID){
$r = $firstName.$lastName;
$membershipID = array_slice ($r, 0, 10);#line 44
}
?>

[/B]

Looks like you're passing a string instead of an array.

byte_me

can i truncate a string as a variable and if so how?

LordShryku

sure, use [man]substr[/man]

byte_me

OK done that but do not seem to get what I expected.

<?php
function MakeID ($firstName, $lastName, $results, $membershipID){
$r = $firstName.$lastName;
$membershipID = substr($r, 10);  

}
?>
<?php
function ShowResults ($firstName, $lastName, $username, $password, $handicapStart, $emailAddress, $county, $clubName, $r, $membershipID)

{echo "These are the details you entered.<br>Please ensure they are correct and click CONFIRMED <br>or user the browsers BACK button to re enter the correct data

   <form action=formresult.php method=post>
<br><FONT COLOR=\"black\" SIZE=\"+1\">Name = $firstName $lastName <br>Username = $username<br>
$r = $firstName.$lastName;
$membershipID = substr($r, 10); 

fullname = $r<br>     #would have expected value of $r 
ID No is = $membershipID<br># would have expected value of $membershipID
  Password = $password<BR>
  Current Handicap = $handicapStart<BR>
  Your Email Address = $emailAddress <BR>
County of Home Club = $county<br>
Club Name =  $clubName<br>

  </FONT>
<input type=submit value=confirm>

  </form>



  <UL>\n";

  #foreach ($GLOBALS as $Key=>$Value){
    #echo "<LI>\$GLOBALS[\"$Key\"]=$Value\n";
 # } # End of foreach ($GLOBALS as $Key=>$Value)
  echo "</UL>\n";

} # End of function ShowResults

The result I get is:

Name = fred ege
Username = ryeh
= fred.ege; = substr(, 10); fullname =
ID No is =
Password = tyhyet
etc...

would have expected values of $r and $membershipID to be displayed from the echo?

ClevaTreva

I think you are incorrectly mixing php functions inside an echo. My preference is not to echo html code at all, rather just switch the php off and on around it, using the shorthand php echo (see below) = to output variables. This has the advantage of looking OK to code editors.

Here's the modified code:

<?php 
function MakeID ($firstName, $lastName, $results, $membershipID){ 
$r = $firstName.$lastName; 
$membershipID = substr($r, 10);   

} 
?> 
<?php 
function ShowResults ($firstName, $lastName, $username, $password, $handicapStart, $emailAddress, $county, $clubName, $r, $membershipID) 

{
?>
"These are the details you entered.<br>Please ensure they are correct and click CONFIRMED <br>or user the browsers BACK button to re enter the correct data 
<form action=formresult.php method=post> 
<br><FONT COLOR="black" SIZE="+1">Name = <?=$firstName $lastName?> <br>Username = <?=$username?><br> 
<?
$r = $firstName.$lastName; 
$membershipID = substr($r, 10); 
?>
fullname = <?=$r?><br>
ID No is = <?=$membershipID?><br>
Password = <?=$password?><BR>
Current Handicap = <?=$handicapStart?><BR>
Your Email Address = <?=$emailAddress?><BR>
County of Home Club = <?=$county?><br> 
Club Name =  <?=$clubName?><br> 
</FONT> 
<input type=submit value=confirm> 
</form> 
<UL>
<? 
  #foreach ($GLOBALS as $Key=>$Value){ 
    #echo "<LI>\$GLOBALS[\"$Key\"]=$Value\n"; 
 # } # End of foreach ($GLOBALS as $Key=>$Value) 
?>
</UL>
<?
}
?>

Trevor

byte_me

thanks trev, but I now get:
Parse error: parse error, expecting ','' or';'' in /home/shopping/public_html/golf/newaccount2.php on line 55

line 55 is

<br><FONT COLOR="black" SIZE="+1">Name = <?=$firstName $lastName?> <br>Username = <?=$username?><br>

leatherback

Hi,

try:

 <br><FONT COLOR="black" SIZE="+1">Name = <? echo $firstName." ".$lastName ?> <br>Username = <?=$username?><br>

byte_me

Well the form is now back up without script errors but the
$membershipID still doesn't show and now I get the original form displayed PLUS the results together on first go.

Name = fred asfe
Username = rgrwegr
fullname = fredasfe
ID No is = this should be the $membershipID
Password = erger
Current Handicap = egetghte
Your Email Address = t@f.com

The bit that gives $membershipID

$r = $firstName.$lastName;  

$membershipID = substr($r, 10);  #this bit does not seem to be working

The $membershipID is kinda important for the DB

leatherback

Have you echo-d $r to see wether it has the desired content?

byte_me

Yes $r is the fullname

leatherback

-- I sometime do wonder.. Why don't you try things before asking --

By using this snippet:

$r = "Justaverylongstringtoseetheeffect";   

$membershipID = substr($r, 10);
echo $membershipID;

and looking at the output:

ongstringtoseetheeffect

I concluded you did not look in the manual & did not try echo-ing the different variables, because you would have seen the working of the command:

string substr ( string string, int start [, int length])

So you should use:

$r = "Justaverylongstringtoseetheeffect";   

$membershipID = substr($r, 0, 10);
echo $membershipID;

byte_me

Actually I did read the manual, the problem was in fact that I had read the instruction incorrectly, and missed out the Zero in the argument, which was highlighted by your reply of another argument.

As a coder of Perl and other languages for many years, helped by forums (as I have also helped others) sarcasm is not helpful to those who need real help in the begining. A little patience is required as a responder or moderator of forums.

On a lighter note, thank you for all your help everyone, the script just needs fixing that was broken by the solution and I shall do that by a further post. Let us conclude this by reolving the thread

leatherback

OK,

my apologies for the sarcasm, but your post was just #toomany in a long row of post where the answer was a simple link to the manual of MySQL or PhP..

Just wondering.. -if- you are a programmer in several languages for many years.. Why don't you echo out every step if a script doesn't work? Usually that is the best way to see what is the actual problem?

Just my 2 cents, as a macro-programmer in PhP, IDL, AML for only a few years.

byte_me

2 cents appreciated

Twas what I was trying to do before I shove it in a MySQL DB, hence the earlier questions re the echo. I usually chuck a
print $myvariable;
into the perl script which I then remove later. Am I right this will also work for PHP?

Now I must fix the form so the send function does not appear till the first submit is hit!!!