New to PHP...need some help

jangoux

Hi,

My name is Ivan and I'm new around here and to PHP. I have some minor experience with some programming languages and as i had read through some tutorials, there's no mistery on the PHP syntax. I understood all the examples simply, so i guess i will not have a hard time figuring everything out and develop my first apps.

Anyway, the reason i am posting here is because i need something a little different from what i 've around the internet.

I'm developing a new web-site for my band, and we want it to have a streaming radio, using shoutcast. THe problem is that the server will run from my computer, which has a dynamic IP. Ok, i can correct that using the dydns service. But i need something to change the image when i'm not connect....

Let me try to explain it more clearly : If i am connected, the page shows image x and links to the streaming audio server. Else, it displays image y and links to another page.

The biggest problem there is how to verify if I am on line or not. How can i do such a thing ? Is there a function or something like it that could verify my IP and put the IP on the page whenever i logged in there, or connected or whatever ?

Thanks,
Ivan Jangoux

jangoux

I also thought of something like a login/logout system. When i log in, the script would pick my IP, change the link on the page and it's image, and when i logged out, it would go back to the previous status. The problem would be that i would need to keep my web browser open all the times that i wanted to appear connected on the home page, right ? And i would also need to do that on a separate page, so others would not see it, right ? Is there any way to get the value of a script running on a page and send it to other script ?

Thanks,
Ivan Jangoux

weekender

use [man]fopen[/man]. You can either put in a domain or an ip

$fp = @fopen("http://domain/","r");
if ($fp)
{ echo "<IMG SRC=\"online.gif\">"; }
else
{ echo "<IMG SRC=\"offline.gif\">"; }

Note: The "@" in front of fopen suppresses the error output of the function.

hope that helps. what's your site?

adam

jangoux

It's stigmaonline.net...It's pretty simple right now, i made it mostly so we could have something until we had some spare time to create another. Now i am on vacations and have one month to make it ready...

Anyway, tomorrow i'll take a look at your code and see if i can make something out of it 🙂