Using the file name as a variable

d-woo

How do I use the filename as a variable?

e.g If I have a filename "DSL-2004-01-03.php" and another filename "56K-2004-01-03.php"

I want to set the value of the variable $speed = "DSL" or "56K" based on the first 3 letters of the filename.

Thanks

leatherback

WHat do you wan to know? How to get a substring (substr(), or how to get a filename in a variable?

aspbyte

Hmm.. your question is prettty interesting if I understand what your trying to say... Look up

dirname(FILE)
and
basename

Rgds
Pradeep

www.phpforme.com

d-woo

Thanks aspbyte...I will look that up.

Leatherback,

I needed to know how to get the filename into the php as a variable.

The substr will definitely be needed and is the second step.

Thanks guys!

LordShryku

Where's the file located? How are you going to determine the filename? Do you need to know how to set the filename as a variable or how to pull the speed from it?

$path = "/home/public_html/DSL-2004-01-03.php";
$file = basename($path); // returns DSL-2004-01-03.php
$speed = substr($file,0,3); // returns DSL

d-woo

Thanks Shryku,

Where is the file located? ....

Sorry about not being clear on that point.

The file is itself.

Therefore if I have a file named DSL-2004-01-04.php

Inside that actual file I want to use the name of the file to set the variables for
$speed = 1st 3 characters of the filename
$date = last 10 characters of the filename

This way all I have to do is rename the file to 56K-2004-01-04.php
and the variables change automatically without any code adjustments.

Likewise renaming the file and changing the date.

For those curious as to why such coding, I have an asx file with the exact same filename.asx which streams a windows media video file (WMV) with the exact same filename.WMV.

Thanks.

LordShryku

Okay, so you should be able to use php_self for this

$file = basename($_SERVER['PHP_SELF']);
$speed = substr($file,0,3);

d-woo

Got it....posting solution for others

inside of a file named DSL-2004-01-04.php

<?php
echo("File Name = ".basename ($PHP_SELF)."<p>");  // returns DSL-2004-01-04.php

//simplified coding
$file = basename ($PHP_SELF);

$speed = substr($file,0,3); 
echo "Speed = ".$speed."<p>"; // returns DSL

$date = substr($file,4,10); 
echo "Date = ".$date."<p>"; // returns 2004-01-04
?>

Thanks guys for leading me on the correct paths to the answer.

php.Net can be difficult when you don't know how to ask for what you need.
🆒