I need simple EXIF help

Carl_Conrad

I've spent the last two hours looking for a simple, straight-forward resource that will explain to me how to get the EXIF data out of the jpegs I upload to my webserver using PHP and have come up with nothing.

So far what I've found has been this, a non-working demo from a PHP manual.

<?php

echo "libys.jpg:<br />\n";
$exif = exif_read_data('libys.jpg', 'IFD0');
echo $exif===false ? "No header data found.<br />\n" : "Image contains headers<br />";

$exif = exif_read_data('libys.jpg.jpg', 0, true);
echo "libys.jpg:<br />\n";
foreach ($exif as $key => $section) {
   foreach ($section as $name => $val) {
       echo "$key.$name: $val<br />\n";
   }
}
?>

Can anyone give me any tips? I just want to print the EXIF data. Does anything need to be installed or running? It's amazing how little I've found on the subject...it just seems as if any writing on it ignores the simple facts and takes for granted that everyone is familiar with EXIF.

Thanks in advance...

jayant

<?php 

echo "libys.jpg:<br />\n"; 
$exif = exif_read_data('libys.jpg', 'IFD0'); 
echo $exif===false ? "No header data found.<br />\n" : "Image contains headers<br />"; 

$exif = exif_read_data('libys.jpg', 0, true); 
echo "libys.jpg:<br />\n"; 
foreach ($exif as $key => $section) { 
   foreach ($section as $name => $val) { 
       echo "$key.$name: $val<br />\n"; 
   } 
} 
?>

Carl_Conrad

Thanks for taking a look. I didn't catch that. Unfortunatly I still have the problem.

libys.jpg:

Fatal error: Call to undefined function: exif_read_data() in /home/mcconaha/public_html/photoblog/exif2.php on line 4

Thoughts?

Weedpacket

[man]exif_read_data[/man]
Note: This function is only available in PHP 4 compiled using --enable-exif. Its functionality and behaviour has changed in PHP 4.2. Earlier versions are very unstable.

So, if you're using a Un*x system, look at php_info() and see if PHP is configured with it. On Windows you'll need to enable php_exif.dll in php.ini

tomwerner

Have a look at this class, it doesn't need the exif libraries compiled it uses native php functions:

http://offsky.com/software/exif/index.php

hth

Carl_Conrad

Wow, thanks tomwerner, that worked perfectly. Any tips on formatting the output though?

tomwerner

From the example in the ZIP file I see that $result is echoed out, so you can access data individually by doing things like:

echo $result['IFDO']['DateTime']; # Echoes date + time of pic
echo $result['IFDO']['Make']; # Echoes Camera Manufacturer

You could echo these variables anyway including in a table if you wanted eg.

print ("<TABLE><TR><TD>Manufacturer</TD><TD>{$result['IFDO']['Make']}</TD></TR>
<TR><TD>Date / Time</TD><TD>{$result['IFDO']['DateTime']}</TD></TR></TABLE>");

Is this what you mean?

Carl_Conrad

Exactly. Thank you.

Carl_Conrad

tomwerner: After playing with the formatting you suggested, I'm still having trouble. I'm not able to print out anything other than how it comes out of the box.

I have it set up here . I used your suggestions from the other post, but the don't seem to do anything. They are above and below "teststestststststst", and the table code is below that.

I'm obviously fairly new at PHP, and I really appriciate your patience with me.

The code for that page is below...

<HTML><BODY>
<?php
//This page just shows how you would use my library.  

//Look in exif.php for more information
//Enjoy.


include('exif.php');

$path="libys.jpg";
$verbose = 0;

$result = read_exif_data_raw($path,$verbose);	
echo "<PRE>"; 
print_r($result); 
echo $result['IFDO']['DateTime']; # Echoes date + time of pic 
echo $result['IFDO']['Make']; # Echoes Camera Manufacturer
echo "teststestststststst";
echo $result['IFDO']['DateTime']; # Echoes date + time of pic 
echo $result['IFDO']['Make']; # Echoes Camera Manufacturer

print ("<TABLE><TR><TD>Manufacturer</TD><TD>{$result['IFDO']['Make']}</TD></TR> 
<TR><TD>Date / Time</TD><TD>{$result['IFDO']['DateTime']}</TD></TR></TABLE>");

echo "</PRE>";

?>

<IMG SRC="thumb.php?path=<?=$path?>">	


</BODY></HTML>

tomwerner

You may might have some luck taking the ' from the variables, I don't know why but it might, you could also try changing the ' with a ". I can give you a better answer when I can get home in a few hours to test the script, (at college at the moment). I think it is nearly there just some tinkering is needed. You could also try doing

var_dump($result);

this is similar to print_r but it may show something up, beware the format is not as uniform. I will try and post again tonight when I can get to a php debugger ;-)

tomwerner

Just spotted something , I think IFDO is actually IFD0 (notice the difference), O is the lettter wheras it should be the number zero!

I F D ZERO

hth

Carl_Conrad

The 0 totally fixed it. Thanks for all your help...its been great.