$_SERVER['REMOTE_ADDR'] problem

Skyld

To my understanding, $SERVER['REMOTE_ADDR'] returns the IP address of your computer.
I am making a PHP script that checks the USER's IP address to see if its on AOL (because my website WONT do AOL Registrations for some reason).
I'm doing this:

$ipr = "217";
$aol = substr("{$_SERVER['REMOTE_ADDR']}",0,3);
echo $aol;

I had the index.php file running through IIS and got 127, and on my site skyld.icekiller.net and got 195. But my IP range at the time was 217. Any ideas? ($ipr was the IP range it was checking for- is supposed to be 172 but changed to 217 to test)

weekender

it's all to do with the network your computer is on.

any network sockets on the current computer have the hostname localhost - and the ip 127.0.0.1 - this is where the 127 comes from

if you're behind a router and/or firewall, you probably have NAT active. This gives everyone inside the router a network IP, although on the internet every computer inside your router will show the net ip - ie it is translated. Most NAT's use ip's in the form 195.168.0.* - this is where your 195 ip comes from.

My guess is your website is currently running on your computer - so it is inside the firewall, and any hits from the same computer will come up as 127.0.0.1 and any hits from inside the firewall (ie your network) will appear as 195...

adam

Skyld

I know about 127.0.0.1 and localhost, and I'm not behind a router or firewall. I cant really see any reason for it to do it.

mogster

Maybe it is (although you don't use a firewall) showing the forwarded ip from a proxy or something?

## Function for finding value from two strings ##
function c_Cval($val_n, $val_o) {
if($val_n) {
$str = $val_n;
} else {
$str = $val_o;
}
return $str;
}

if(c_Cval($_SERVER['HTTP_X_FORWARDED_FOR'], $HTTP_SERVER_VARS['HTTP_X_FORWARDED_FOR'])) { 
$ip = c_Cval($_SERVER['HTTP_X_FORWARDED_FOR'], $HTTP_SERVER_VARS['HTTP_X_FORWARDED_FOR']);
} else { 
$ip = c_Cval($_SERVER['REMOTE_ADDR'], $HTTP_SERVER_VARS['REMOTE_ADDR']);
}

Possible?

knutm :-)