Post

moniphp

Please someone help me. Here is what I want to do: when I am in page prueba.php and click the submit button I want to go to prueba2.php and send the variable cod. The problem is that in prueba2.php I can´t read the value of cod.
Here is a piece of the code of prueba.php:

echo" <body>";
echo" <form action='prueba2.php?cod=$cod' method='post' name='form1'>";
echo" <p align='center'><font size='5'><b>Formulario de Solicitud de Cables</b></font></p>";

if(!(empty($cod)))
{
$cod=2;
echo "Estoy en el if";
}
else
{ $cod=0;
echo "Estoy en else";
}

I even try to declare cod as hidden:
echo" <input type='hidden' name='cod'>";
but it doesn't work either.
I reaaly apprecciate any help.
Thanks.

leatherback

-> have a read through the frequently asked questions thread. It is there to answer the most frequently asked questions.<-

The solution to your problem is there.

anyway. You need to use $_POST[cod] most likely.

moniphp

I tried that to but still not working

swr

Try this:

echo "<input type='hidden' name='cod' value='$cod'>";

The value part was missing from the hidden form tag you posted, which means it would not get any value.

Embedding the variable into the form URL is usually not a good idea because the form is going to do its own thing to submit variables. Hidden fields are better.