undefined variable?

[osusano]

if($test != ''){ 
   print 'test'; 
}

this script give an undefined variable error.

how can u solve this kind of problem?

thank you in advance.

[AstroTeg]

Assign $test to something first. Like:

$test = '';
if($test != '')
  print 'test';

[osusano]

well bascially that will do.. but i dont like assigning the test coz i want to get the test from the form. but im not saying that the value of the of the $test has always content and it will going to get even a blank or space value..

so how do u fix this?

[AstroTeg]

You need to get the value from the form then. Lets assume you're using post to submit the form:

$test = $_POST['test'];

Or something like that will do. Then your if() should work fine...

[ahundiak]

Or check to see if the variable has any value before using.

if (isset($test)) {
  // Know it has something
}

[osusano]

problem solve by configuring something from php.ini

thanky ou anyway 🙂

[AstroTeg]

Don't tell me you're turned register_globals on... smacks forehead

[philipolson]

I'm guessing the PHP directive error_reporting was turned way down as to make all those warnings and notices automagically disappear! Good little programmers code with E_ALL and don't create errors like E_NOTICE all over the place... just something to keep in mind 🙂