Windows 2003 server PHP include variable

[sylunt1]

What I am trying to do is this:
I have an include file called fnctpage.php. If this file exists in the sams directory as the file that is calling it - it works. If the fnctpage.php file is not in that directory then it gives the error:

Warning: main(fnctpage.php): failed to open stream: No such file or directory in E:\Websites\site.com\folder\file.php on line 20.

I know in linux you can use a statement such as $_SERVER[‘DOCUMENT_ROOT’] to echo the path (E:\Websites\site.com) instead of hard coding it in (hardcoding it works just fine - but I would rather use a variable). Is there a way to get this to work?

Thanks,
Chris

[devinemke]

If you don't specify a path in your include() statement then the file is assumed to be in the same directory. If not you can use other relative path tricks. For example, if "fnctpage.php" is in one subfolder down from your script called "includes" then you can do:

include ('./includes/fnctpage.php');

$_SERVER[‘DOCUMENT_ROOT’] and most other PHP predefined environmental variables will be available in all OS's to create a dynamic absolute path.

You can also specify an "include_path" in your php.ini file to search common directories for included files.

[sylunt1]

Thanks for the reply. I tried using the /../ type method and no luck. The site is hosted elsewhere so I don't have access to the php.ini file.

I don't know if it is a security thing by the host or what...