Checkboxes with Forms

zulx

Hi,

What I wanted to do was to have the user to
1.) select a few options on xxx.html with the dictated checkboxes
2.) and the user choice will be transfer to the yyy.php page
2.a) printing/confirming his options on the yyy.php page - with a string of characters minus the checkboxes

I have tried using a lot of methods but the selected choices will not show up on the yyy.php page.

Here's an abstract of what I have done:

for xxx.html ->

<form action="data_choice.php" method="POST">
<input type="checkbox" name="checkbox1"/>
<B>Weight</B><BR/>
Measured to the nearest 0.5kg<BR/><BR/>
</form>

for yyy.php ->

<?php
$checkbox1 ='weight';
if($_POST['checkbox1'] == 1) echo strlen($checkbox1);

?>

yyy.php
<?php
$checkbox1 =$_POST['checkbox1'];
if($checkbox1 == 1) print("Weight<br>"; )
?>

Any ideas of what went wrong with my codes?

Erkilite

the post values for check boxes won't be set unless they are actually checked.

try something like

if(isset($_POST['checkbox'])){
echo 'checked';
} else {
echo 'not checked';
}

zulx

Originally posted by Erkilite
the post values for check boxes won't be set unless they are actually checked.

try something like

if(isset($_POST['checkbox'])){
echo 'checked';
} else {
echo 'not checked';
}

Hi Erkilite,

Do I put this into xxx.htmlor yyy.php?

Erkilite

yyy.php

the page that the information actually gets posted to.

zulx

Originally posted by Erkilite
yyy.php

the page that the information actually gets posted to.

now the yyy.php when viewed appears with ->

Your Selection:

Not Checked

How can I get it to print out the option that was checked?
e.g.

Your Selection:

Weight

zulx

Originally posted by Erkilite
yyy.php

the page that the information actually gets posted to.

now the yyy.php when viewed appears with ->

Your Selection:

Not Checked

How can I get it to print out the option that was checked?
e.g.

Your Selection:

Weight

Erkilite

set a value for the check box

then use

echo $_POST['wefwef'];

zulx

It still doesnt work. Now it only appears with:

Your Selection:

not checked

No matter whether I selected the the checkbox or not on xxx.html. Here's what i have altered my scripts to.

xxx.html ->
<FORM ACTION="yyy.php" METHOD="POST">
<input type="checkbox" name="checkbox1" value="value" />
<B>Weight</B><BR/>
Measured to the nearest 0.5kg<BR/><BR/>
</FORM>

yyy.php ->
<?php
if(isset($POST['checkbox1'])){
echo $POST['checkbox1'];
} else {
echo 'not checked';
}
?>

Erkilite

you need a submit button on the form,

i just tested it and it works fine for me.

zulx

Its works fine now. CHeers!

However it will now work if my submit button was outside the form. I have designed a submit buttom with an rollover image but when i placed in within the form, the same problem of "not checked" repeats.

Another question is, how can I get it not to print anything when it checks the if-statement and finds it unchecked?

Erkilite

remove this part of code

' else {
blah blah
}'

zulx

What can I say. You are a star! 😃
Work just like what I want it to be now.

Just have to figure how to get the submit button that i designed with the swap images function to work outside the form now.

Cheers!

Erkilite

give your form a name

ie. <form action="ewfefwfe" method="post" name="myform">

use the onclick function for the image to do something like

webzyne

How would you get it to ONLY show the ones that were checked instead of saying "Not Checked" for the unchecked ones?

Or am I misreading?

zulx

How can I compromise the onlick to onMouseOver instead?

Erkilite

i don't think the mouseover would affect the onclick of the image, the on mouse over i think only changes the src attribute.

however, you could put the onclick in the href if you wanted.

zulx

I've tried doing this before the form starts but it will not work. Here's what I have done:

<FORM ACTION="choiceSelf.php" METHOD="POST" name="choiceSelf">
<input type ="submit" value="Select"><BR/>
<input type="checkbox" name="checkbox1" value="Weight" />
<B>Weight</B><BR/>
Measured to the nearest 0.5kg<BR/>
</FORM>

The button that will show me the correct results is the one in the form and not the one outside the form.

Erkilite

you need to remove the link in the href field.

try setting href="#" or just removing the href link altogether and putting the mouse over and onclick in the image tag.

zulx

the href "#" works, Cheers Mate!