Ok I tried replacing this line:
$query = "SELECT id, format_type FROM reviews2_format ORDER BY format_type ASC";
with this one:
$query = "SELECT id, format_type FROM reviews2_format WHERE format_type NOT LIKE {book_%} ORDER BY format_type ASC";
and I also tried with this one:
$query = "SELECT id, format_type FROM reviews2_format WHERE format_type NOT LIKE book_% ORDER BY format_type ASC";
but that didn't work.
The page returns:
Warning: mysql_free_result(): supplied argument is not a valid MySQL result resource in /home/virtual/site372/fst/var/www/html/reviews/admin/main.inc on line 136
and the drop down menu contains no items at all...
line 136 is this:
mysql_free_result($result);
what did I do wrong?