why is it returning query was empty?

[SeenGee]

like the title says, getting a "Query was empty" error message, this is a section of code that i am trying to use for a search facility on my site.

<?
if ($action=='keywordsearch')
	{//if action

	$sql = "SELECT * FROM products WHERE UPPER(CONCAT(`productid` , `brand` , `code` , `printer` , `rrp` , `price` , `availability` , `status` , `type` , `productsort` , `category` , `view` )) LIKE UPPER('%$keysearchstr%') LIMIT 0, 30";
	//echo $sql;
	echo '<br />'; 
	$result = mysql_query($sql) or die(mysql_error());
	$numResults = mysql_num_rows($result);

		if($numresults == 0)
		{
			$i =  (strlen($keysearchstr) - 1);//checks str length and takes one away: for array position in substr
			$newString = $keysearchstr;
			$str1 = $newString{0};
			$str2 = $newString{$i};
			//$newkeysearchstr = $str1."%".$str2;
			//echo $newkeysearchstr;

			$newSql = "SELECT * FROM products WHERE UPPER(CONCAT(`productid` , `brand` , `code` , `printer` , `rrp` , `price` , `availability` , `status` , `type` , `productsort` , `category` , `view` ))  LIKE UPPER ('$str1%$str2') LIMIT 0, 30";
			echo $newSql;
			$newresult = mysql_query($newsql) or die(mysql_error());
			$newnumResults = mysql_num_rows($result);
		}

		else if(($numResults >0)||($newnumresults >0))
			{//if results >0
			echo '<table border="0" class="mainBox" width="100%">';
			echo '
					<tr>
						<td colspan="8">
							Ink
						</td>
					</tr>
					<tr>
						<td align="center" width="10%">
							Code
						</td>
						<td width="30">&nbsp;</td>
						<td>
							Printer
						</td>
						<td align="center">
							RRP
						</td>
						<td align="center">
							Our Price
						</td>
						<td align="center">
							You Save
						</td>
						<td align="center">
							Qty
						</td>
						<td></td>
					</tr>
					';
						while ($inkrow = mysql_fetch_object($result))
							{//while

								$productid=$inkrow->productid;
								$rrp=$inkrow->rrp;
								$price=$inkrow->price;
								$imagename=$inkrow->type;
								$image='<img src="icons/'.$imagename.'.gif" alt="'.$imagename.'" />';
								$class=$inkrow->availability;
								echo '<tr class="'.$class.'">';
								?>
									<td>
								<? echo $inkrow->code; ?>
									</td>
									<td align="center">
										<? echo  $image; ?>
									</td>
									<td>
										<? echo $inkrow->printer; ?>
									</td>
									<td align="center">
										<? echo $rrp; ?>
									</td>
									<td align="center">
										<? echo $price; ?>
									</td>
									<td align="center">
										<?

										$portion=($price/$rrp);
										$percentage=round((100*(1-$portion)), 1);
										echo ''.$percentage.'%<br />';							

										 ?>
									</td>
									<td align="center">
										<? 
										if ($class=='out') {
											echo '<a href="outofstock.php" title="Out of Stock.  Click for more info">*</a>';
										}
										else {
											echo '<a href="basket.php?action=add&id='.$productid.'">add</a>'; 
										}

										?>
							</td>					
						</tr>
						<?
							}//while
			echo '</table>';
	}//if results>0

}//close if action

Database is connecting, everything working until the second sql call, when i comment out this code the search runs, not that accurate but it works, when i add second sql call gives the error message.

Any ideas please?

[SeenGee]

seen my error, $newsql and $newSql were used as the same thing. still getting an sql syntax error though.