php-cli

Butthead

I'm using php-cli for the first time (i like it i liiiike iiiit). I have a question, how would you read in flags from the cli?

./test.php -e foo -l bar

Is there a tutorial on this somewhere? I'm going to start using this instead of perl, and bash in some cases. For one thing I'm a lot better with php.

ahundiak

$SERVER['argc'] and $SERVER['argv']

Works just like their C counter parts.

You might look at the PEAR console class if you plan on doing a bunch of arg parsing.

Sxooter

I thought even with global vars turned off, the cli version had direct access to $argc and $argv[]

ahundiak

I thought even with global vars turned off, the cli version had direct access to $argc and $argv

True but they are not super globals so you can't get at them inside of functions without using $_SERVER or the global keyword. Personal preference I guess.

Sxooter

True, but input args should be parsed FIRST, assigned to properly named vars, and then unset or ignored.

to me, accessing the input args all over your code is bad practice. Grabbing them right up front, range checking them, and spitting out errors should they be wrong is the "right way" (TM) to do it .

Butthead

uhhhh you got any examples?

:-)

All my test code so far is pretty busted. I must be missing something as I just don't see how to associate the argument with the right flag.

ie. ./test.php -a foo -b bar

if i check argv, argv[1] gets -a argv[2] gets foor etc...this would mean that everything would have to be in the right order to work (at least according to my limited mind ;-). What if someone passed ./test.php -b bar -a foo? My scripts would fail. I'm just not understanding how the flag and it's argument are grouped. :-(

Sxooter

<?php
if ($argc!=3) die ("Usage:\n\timport groupname filename\n");
$group = $argv[1];
$filename = $argv[2];
# more code goes here
?>

Butthead

It crystal clear now.

thanks!