If statement error

[Rulkster]

This is how I am writing my if statement:

if (($olddata !="y") || ($olddata !="n")) {
.
.
.
.
}

However, I am getting a parse error. The only values that $olddata can accept is "y" or "n". What is wrong with the above code or should I be writing it differently.

Thanks

[LordShryku]

I think you really need to use AND instead of OR if you're checking for not equal.

if($olddata != "y" && $olddata != "n") {
   // error
}

OR would work if you were checking for equality

if($olddata == "y" || $olddata =="n") {
   // then it's ok
}

[drew010]

chances are your parse error is above that line and its reporting it because you left out a semicolon above. check the previous lines because nothing looks wrong with it.