another file uploading question

Lcousins

Hi all,

1st up I can already do this by using the many scripts ive either found online or have been kindly made by users of this and other forums but I still dont fully understand what does what in the code.

forgetting all the security and error checking for a moment, what would be the simplest code to upload a file (assuming the form to pick the file has 'userfile' as the variable name) into a folder contained in the same folder as the uploading script.

If someone can show me this I can hopefully ask the questions i need answering by using it as anexample

thanks

Luke

The_Chancer

copy($_FILES['userfile']['tmp_name'], $the_path . "/" .$newname)

Does the trick - remember to use the enctype=multipart/form-data though...

Lcousins

thanks thats great, now for the questions!

using the example above:

'enctype=multipart/form-data' what is that telling the server? whats the equivelant for a form that doesnt upload anything?
'$newname' whats this supposed to represent? is it the same as '$userfile_name'?
$_FILES['userfile']['tmp_name'], erm, i must admit to not being sure whats happening here at all, where does 'tmp_name' come from and what is the effective output of just this peice of code?

hope those questions all make sense, I realise I could just keep on using the scrpts that I know work but have this irrepressable urge to understand everything i use 😉

luke

The_Chancer

As to the enctype - that is a matter for the W3C - Not too hot on my full standards, but I know it is required to upload a file...

When you are uploading a file - it is accessible through the $_FILES global array, which holds a few things - like
[name] - its original name
[tmp_name] - temp uploaded name
[size] - its size
[type] - the filetype

So you can refer to it as $_FILES['userfile'] is the array of all the above parts from the uploaded file, then add one of the above to get what you want.

$newname is the name of the file once it has been uploaded - you could use $_FILES['userfile']['name'] to keep the name the same...

Lcousins

Thankyou!! that was the missing link in my logic, i didnt realise you could extract the upload details seperately using that form, hence i aassumed they must be variables I was supposed to be declaring somewhere...

can be closed now if thats the way things work around here 🙂

luke

Shawazi

Why doesn't this work? I found this with search I know it's old.

$userfile = $pdf[$c];
$file = $_FILES['$userfile']['name'];
$file2 = $_FILES['$userfile']['tmp_name'];
echo "<hr>$file | $file2 | $userfile<hr>";

It only outputs userfile as the tmp location /tmp/phpje8L8B

Shawazi

			foreach ($_FILES[pdf] as $key => $value)
			{
				if ($key == "name")
				{
						$file = $value[1];			
				}
			}

got it