[Resolved] Why @?

jonki

I have been trying to figure out what the "@" does infront of a command.

If I search for @ I am told that it is under the minimum word length so I get no results and the book I have doesn't index it either.

Another (perhaps trivial) question - why do I have to create an image from a jpeg when my image is already a jpeg?

@imagecreatefromjpeg($im_name);
@imagecopyresized ....etc .....

Just curious - I like to understand what I am doing rather than just copy and paste code.

Thanks a lot.

Jon

olaf

It's a kind validator...

If function ok do it , otherwise do not.

piersk

Sorry, but you're wrong. It's actually an Error Control Operator.

here comes the science bit...

if($variable == "thing")
{
do this
}

if $variable has not been set, then this will come out with an error. However, if you do this:

if(@$variable == "thing")
{
do this
}

then all will be fine and dandy (but if $variable isn't equal to "thing" or it hasn't been set yet, then "do this" will no happen)

planetsim

However @ shouldnt be used not in the development process anyway. I wont say what forum app uses it a lot.

olaf

maybe i used the wrong words....

lyingbuddha

If you use @

@mysql_connect($dbhost,$dbuser,$dbpass)
or die ("Can not connect to server. Sorry.");

the error message will be displayed like you've defined;
Can not connect to server. Sorry.

If you remove the @
you'll see the error message exact, like:
Warning: mysql_connect(): Access denied for user: blah blah...

so it'lll be easier to understand your mistake.

Don't use @ sign till your code is finished. When you're done with the code, add the @ sign to display "let's less inform lamer" error message that you'll chose.

jonki

Cheers guys - that helps a lot.

I really appreciate it.

Jon